Skip to content
Related Articles
Get the best out of our app
GeeksforGeeks App
Open App
geeksforgeeks
Browser
Continue

Related Articles

Construct Pushdown automata for L = {0n1m2m3n | m,n ≥ 0}

Improve Article
Save Article
Like Article
Improve Article
Save Article
Like Article

Prerequisite – Pushdown automata, Pushdown automata acceptance by final state
Pushdown automata (PDA) plays a significant role in compiler design. Therefore there is a need to have a good hands on PDA. Our aim is to construct a PDA for L = {0n1m2m3n | m,n ≥ 0}

Examples –

Input : 00011112222333
Output : Accepted

Input : 0001122233
Output : Not Accepted

Approach used in this PDA –
There can be 4 cases while processing the given input string.

  • Case-1: m = 0 – In this cases the input string will be of the form {0n3n}. In this condition, keep on pushing 0’s in the stack until we encounter with 3. On receiving 3 check if top of stack is 0, then pop it (0) from the stack. Pop 0’s until all the 3’s of the input string are processed. If we reach to the end of input string and stack becomes empty, then reach to final state i.e. accept the input string else move to dead state.
  • Case-2: n = 0 – In this cases the input string will be of the form {1m2m}. In this condition, keep on pushing 1’s in the stack until we encounter with 2. On receiving 2 check if top of stack is 1, then pop it (1) from the stack. Keep on pop 1’s until all the 2’s of the input string are processed. If we reach to the end of input string and stack becomes empty, then reach to final state i.e. accept the input string else move to dead state.
  • Case-3: m, n>0 – In this cases the input string will be of the form {0n1m2m3n}. In this condition, keep on pushing 0’s and 1’s in the stack until we encounter with 2. On receiving 2 check if top of stack is 1, then pop it (1) from the stack. Keep on pop 1’s until all the 2’s of the input string are processed. Then on receiving 3 check if top of stack is 0, then pop it (0) from the stack. Pop 0’s until all the 3’s of the input string are processed. If we reach to the end of input string and stack becomes empty, then reach to final state i.e. accept the input string else move to dead state.
  • Case-4: m = 0, n = 0 – In this case the input string will be empty. Therefore directly jump to final state.

Final Pushdown automata for the given language is:

My Personal Notes arrow_drop_up
Last Updated : 20 Jul, 2018
Like Article
Save Article
Similar Reads