conj() function in C++ with Examples

The conj() function is defined in the complex header file. This function is used to find the conjugate of the complex number z. If we represent a complex number z as (real, img), then its conjugate is (real, -img).

Syntax:

template<class T> complex<T> 
     conj (const complex<T>& Z);

Parameter:

  • z: This method takes a mandaory parameter z which represents the complex number.

Return value: This function returns the conjugate of the complex number z.

Below programs illustrate the conj() function for complex number in C++:

Example 1:-

filter_none

edit
close

play_arrow

link
brightness_4
code

// C++ program to demonstrate
// example of conj() function.
   
#include <bits/stdc++.h>
using namespace std;
   
// driver program
int main ()
{
  complex<double> complexnumber (3.0, 2.4);
   
  cout << "The conjugate of " << complexnumber << " is: ";
   
  // use of conj() function
  cout << conj(complexnumber) << endl;
  return 0;
}

chevron_right


Output:

The conjugate of (3,2.4) is: (3,-2.4)

Example 2:-

filter_none

edit
close

play_arrow

link
brightness_4
code

// C++ program to demonstrate
// example of conj() function.
   
#include <bits/stdc++.h>
using namespace std;
   
// driver program
int main ()
{
  complex<double> complexnumber (2.0, 9.0);
   
  cout << "The conjugate of " << complexnumber << " is: ";
   
  // use of conj() function
  cout << conj(complexnumber) << endl;
  return 0;
}

chevron_right


Output:

The conjugate of (2,9) is: (2,-9)


My Personal Notes arrow_drop_up

Check out this Author's contributed articles.

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.




Article Tags :
Practice Tags :


Be the First to upvote.


Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.