ConcurrentSkipListSet remove() method in Java
The java.util.concurrent.ConcurrentSkipListSet.remove() method is an in-built function in Java which is used to remove an element if it is present in this set.
Syntax:
ConcurrentSkipListSet.remove(Object o)
Parameters: The function accepts a single parameter o i.e. the object to be removed.
Return Value: The function returns a true boolean value on successful removal of the object, otherwise returns false.
Below programs illustrate ConcurrentSkipListSet.remove() method:
Program 1: The element to be removed is present in the set.
import java.util.concurrent.ConcurrentSkipListSet;
class ConcurrentSkipListSetRemoveExample1 {
public static void main(String[] args)
{
ConcurrentSkipListSet<Integer> set =
new ConcurrentSkipListSet<Integer>();
for ( int i = 1 ; i <= 5 ; i++)
set.add(i);
System.out.println( "The elements in the set are:" );
for (Integer i : set)
System.out.print(i + " " );
set.remove( 1 );
set.remove( 5 );
System.out.println( "\nRemaining elements in set : " );
for (Integer i : set)
System.out.print(i + " " );
}
}
|
Output:
The elements in the set are:
1 2 3 4 5
Remaining elements in set :
2 3 4
Program 2: The element to be removed is not present in the set.
import java.util.concurrent.ConcurrentSkipListSet;
class ConcurrentSkipListSetRemoveExample2 {
public static void main(String[] args)
{
ConcurrentSkipListSet<Integer> set =
new ConcurrentSkipListSet<Integer>();
for ( int i = 10 ; i <= 15 ; i++)
set.add(i);
System.out.println( "The elements in the set are:" );
for (Integer i : set)
System.out.print(i + " " );
set.remove( 1 );
set.remove( 5 );
System.out.println( "\nRemaining elements in set : " );
for (Integer i : set)
System.out.print(i + " " );
}
}
|
Output:
The elements in the set are:
10 11 12 13 14 15
Remaining elements in set :
10 11 12 13 14 15
Reference: https://docs.oracle.com/javase/8/docs/api/java/util/concurrent/ConcurrentSkipListSet.html#remove-java.lang.Object-
Last Updated :
17 Sep, 2018
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