ConcurrentSkipListSet first() method in Java
Last Updated :
17 Sep, 2018
The first() method of java.util.concurrent.ConcurrentSkipListSet is an in-built function in Java which returns the first (lowest) element currently in this set.
Syntax:
ConcurrentSkipListSet.first()
Return Value: The function returns the first (lowest) element currently in this set.
Exception: The function throws NoSuchElementException if this set is empty.
Below programs illustrate the ConcurrentSkipListSet.first() method:
Program 1:
import java.util.concurrent.ConcurrentSkipListSet;
class ConcurrentSkipListSetFirstExample1 {
public static void main(String[] args)
{
ConcurrentSkipListSet<Integer>
set = new ConcurrentSkipListSet<Integer>();
set.add( 10 );
set.add( 35 );
set.add( 20 );
set.add( 25 );
System.out.println( "The lowest element in the set: "
+ set.first());
}
}
|
Output:
The lowest element in the set: 10
Program 2: Program to show NoSuchElementException in first().
import java.util.concurrent.ConcurrentSkipListSet;
class ConcurrentSkipListSetFirstExample2 {
public static void main(String[] args) throws InterruptedException
{
ConcurrentSkipListSet<Integer>
set = new ConcurrentSkipListSet<Integer>();
try {
System.out.println( "The lowest element in the set: " +
set.first());
}
catch (Exception e) {
System.out.println( "Exception :" + e);
}
}
}
|
Output:
Exception :java.util.NoSuchElementException
Reference: https://docs.oracle.com/javase/8/docs/api/java/util/concurrent/ConcurrentSkipListSet.html#first–
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