CompoundName compareTo() method in Java with Examples

Last Updated : 27 Mar, 2020

The compareTo() method of a javax.naming.CompoundName class is used to compare this CompoundName with the specified object passed as a parameter. It returns a negative integer, zero, or a positive integer as this CompoundName object is less than, equal to, or greater than the given Object as a parameter. If the passed object is null or not an instance of CompoundName then the ClassCastException is thrown by this method.

Syntax:

public int compareTo(Object obj)

Parameters: This method accepts obj which is the non-null object to compare against.

Return value: This method returns a negative integer, zero, or a positive integer as this Name is less than, equal to, or greater than the given Object.

Exception: This method throw ClassCastException if passed obj is not a CompoundName object.

Below programs illustrate the CompoundName.compareTo() method:
Program 1:

// Java program to demonstrate 
// CompoundName.compareTo() 
  
import java.util.Properties; 
import javax.naming.CompoundName; 
import javax.naming.InvalidNameException; 
  
public class GFG { 
    public static void main(String[] args) 
        throws InvalidNameException 
    { 
  
        // need properties for CompoundName 
        Properties props = new Properties(); 
        props.put("jndi.syntax.separator", ":"); 
        props.put("jndi.syntax.direction", 
                  "left_to_right"); 
  
        // create compound name object 
        CompoundName CompoundName1 
            = new CompoundName("x:y:z", 
                               props); 
        CompoundName CompoundName2 
            = new CompoundName("x:y:m", 
                               props); 
  
        // apply compareTo() 
        int value 
            = CompoundName1 
                  .compareTo(CompoundName2); 
  
        // print value 
        if (value > 0) 
            System.out.println( 
                "CompoundName1 is "
                + "greater than CompoundName2"); 
        else if (value < 0) 
            System.out.println( 
                "CompoundName1 is "
                + "smaller than CompoundName2"); 
        else
            System.out.println( 
                "CompoundName1 is "
                + "equal to CompoundName2"); 
    } 
} 

Output:

CompoundName1 is greater than CompoundName2

Program 2:

// Java program to demonstrate 
// CompoundName.compareTo() method 
  
import java.util.Properties; 
import javax.naming.CompoundName; 
import javax.naming.InvalidNameException; 
  
public class GFG { 
    public static void main(String[] args) 
        throws InvalidNameException 
    { 
  
        // need properties for CompoundName 
        Properties props = new Properties(); 
        props.put("jndi.syntax.separator", "@"); 
        props.put("jndi.syntax.direction", 
                  "left_to_right"); 
  
        // create compound name object 
        CompoundName CompoundName1 
            = new CompoundName( 
                "x@y@z@M@n", 
                props); 
        CompoundName CompoundName2 
            = new CompoundName( 
                "x@y@z@M@n", 
                props); 
  
        // apply compareTo() 
        int value 
            = CompoundName1 
                  .compareTo(CompoundName2); 
  
        // print value 
        if (value > 0) 
            System.out.println( 
                "CompoundName1 is "
                + "greater than CompoundName2"); 
        else if (value < 0) 
            System.out.println( 
                "CompoundName1 is "
                + "smaller than CompoundName2"); 
        else
            System.out.println( 
                "CompoundName1 is "
                + "equal to CompoundName2"); 
    } 
} 