Compare two integers without using any Comparison operator

Given two integers A & B. Task is to check if A and B are same or not without using comparison operators.
Examples:

Input : A = 5 , B = 6
Output : 0

Input : A = 5 , B = 5 
Output : 1

Note : 1 = "YES" and 0 = "NO"

idea is pretty simple we do Xor of both element ( A , B ) . if Xor is zero then two number are equal else not . 
Below is the implementation of above idea : 

C++

// C++ program to compare two integers without
// any comparison operator.
#include<bits/stdc++.h>
using namespace std;

// function return true if A ^ B > 0  else false
bool EqualNumber(int A, int B)
{
   return ( A ^ B ) ;
}

// Driver program
int main()
{
  int A = 5 , B = 6;
  cout << !EqualNumber(A, B) << endl;
  return 0;
}

Java

// Java program to compare two integers without
// any comparison operator.
import java.util.*;

class solution
{

// function return true if A ^ B > 0 else false
static boolean EqualNumber(int A, int B)
{

  if ((A^B) != 0)
   return true;
  else
   return false;
}

// Driver program
public static void main(String args[])
{
int A = 5 , B = 6;
if(EqualNumber(A, B) == false)
 System.out.println(1);
else
 System.out.println(0);

}
}
// This code is contributed by
// Surendra_Gangwar

Python3

# Python3 program to compare two integers
# without any comparison operator.

# Function return true if
# A ^ B > 0 else false
def EqualNumber(A, B):

    return ( A ^ B )

# Driver Code
A = 5; B = 6
print(int(not(EqualNumber(A, B))))

# This code is contributed by Smitha Dinesh Semwal.

C#

// C# program to compare two integers
// without any comparison operator.
using System;

class GFG
{
// function return true if
// A ^ B > 0 else false
static bool EqualNumber(int A, int B)
{
    if(( A ^ B ) > 0)
        return true;
    else
        return false;
}

// Driver Code
public static void Main()
{
    int A = 5 , B = 6;
    if(!EqualNumber(A, B) == false)
        Console.WriteLine("0");
    else
        Console.WriteLine("1");
}
}

// This code is contributed
// by Akanksha Rai

PHP

<?php
// PHP program to compare two integers
// without any comparison operator.

// function return true if
// A ^ B > 0 else false
function EqualNumber($A, $B)
{
return ( $A ^ $B ) ;
}

// Driver Code
$A = 5 ;
$B = 6;
echo ((int)!(EqualNumber($A, $B))) . "\n";

// This code is contributed
// by ChitraNayal
?>

Javascript

<script>

// JavaScript program to compare two integers without
// any comparison operator.

// function return true if A ^ B > 0 else false
function EqualNumber(A, B)
{
return ( A ^ B ) ;
}

// Driver program

let A = 5 , B = 6;
if(!EqualNumber(A, B) == false)
    document.write("0");
else
    document.write("1");


// This code is contributed by Surbhi Tyagi.

</script>

Output

0

Time Complexity: O(1)

Auxiliary Space: O(1)
Reference :http://stackoverflow.com/questions/476800/comparing-two-integers-without-any-comparison

2^nd Method:

Another Approach is using “-” (Minus/Subtraction Operator). If the Result of Subtraction between the two Numbers is “Zero”, then they are equal (we return ‘1’), else they are not equal (we return ‘0’).

C++

// C++ program to compare two integers
// without any comparison operator.
#include <iostream>
using namespace std;

// Function return 0 if
// A - B != 0 else return 1
int EqualNumber(int A, int B)
{
  int diff = A - B;
  if(diff)
    return 0;
  else
    return 1;
}

// Driver Code
int main()
{
    int A = 5, B = 6;
    cout << EqualNumber(A, B);
    return 0;
}

// This code is contributed by kothavvsaakash

Python

# Python3 program to compare two integers
# without any comparison operator.

# Function return 0 if
# A - B != 0 else return 1
def EqualNumber(A, B):
  diff = A - B
  if(diff):
    return 0
  else:
    return 1

# Driver Code
A = 5; B = 6
print((EqualNumber(A, B)))

# This code is contributed by kothavvsaakash

Output

0

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