A and B are playing a game. At the beginning there are n coins. Given two more numbers x and y. In each move a player can pick x or y or l coins. A always starts the game. The player who picks the last coin wins the game. For a given value of n, find whether A will win the game or not if both are playing optimally.
Input : n = 5, x = 3, y = 4 Output : A There are 5 coins, every player can pick 1 or 3 or 4 coins on his/her turn. A can win by picking 3 coins in first chance. Now 2 coins will be left so B will pick one coin and now A can win by picking the last coin. Input : 2 3 4 Output : B
Let us take few example values of n for x = 3, y = 4.
n = 0 A can not pick any coin so he losses
n = 1 A can pick 1 coin and win the game
n = 2 A can pick only 1 coin. Now B will pick 1 coin and win the game
n = 3 4 A will win the game by picking 3 or 4 coins
n = 5, 6 A will choose 3 or 4 coins. Now B will have to choose from 2 coins so A will win.
We can observe that A wins game for n coins only when it loses for coins n-1, n-x and n-y.
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