Skip to content
Related Articles

Related Articles

Improve Article
Cohesity Internship Interview Experience
  • Difficulty Level : Medium
  • Last Updated : 19 Aug, 2018

Cohesity came to our campus for 2 month internship.It has 1 online round and 2 F2F zoom round each of half hour.

Online round was on HackerRank having 2 question, We have to do it in 1:10 minutes.
Question 1 : Count maximum number of pair (a, b) possible from an array so that a is less than equal to 2*b. Also tell number of unpaired element left.(50 marks)
So for Input
1, 3, 5, 6, 7
ans = 2 1
as 1, 5 and 3, 6 are 2 pair and 7 is the only unpaired elelment left.
Question 2 : Given 2 string, say s1 and s2 find total number of substring such that s[i .. j]=s[k. . l] and j-i+1 is minimal. (20 Marks)
It seems hard, but is simple as j-i+1 should be minimal .One can use count sort to count number of char and then do summation as
where count1 and count2 are 26 length array giving number of times a char occurred in s1 and s2, respectively.

After round 1 only 5 Candidates were shortlisted for interview which had more than 57 marks.

For each Zoom round, We have only 30 min to understand the problem and give its pure C++ code.

Zoom Round 1:

Question : Given a Cyclic Link List Remove adjacent duplicate element.

I/P: 1-2-3-3-2-1
O/P: 2-3-2-1
Answer can be given in Recursive or Iterative approach.
Remember to take edge cases as List can be null or can have only 1 element.

Zoom Round 2: Find Diameter of a Binary tree.

Only 1 candidate was selected for the internship out of 5, me 😉 ..

Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready. To complete your preparation from learning a language to DS Algo and many more, please refer Complete Interview Preparation Course. In case you are prepared, test your skills using TCS, Wipro, Amazon and Microsoft Test Serieses.

My Personal Notes arrow_drop_up
Recommended Articles
Page :