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Class isInterface() method in Java with Examples

  • Last Updated : 31 Dec, 2021

The isInterface() method of java.lang.Class class is used to check if this Class is an interface. The method returns true if this Class is an interface. It returns false otherwise.

Syntax:

public boolean isInterface()

Parameter: This method does not accept any paramter.

Return Value: This method returns true if this Class is an interface. It returns false otherwise.

Below programs demonstrate the isInterface() method.

Example 1:

tabby title=”Java”]




// Java program to demonstrate isInterface() method
  
public class Test {
    public static void main(String[] args)
        throws ClassNotFoundException
    {
  
        // returns the Class object for this class
        Class myClass = Class.forName("Test");
  
        System.out.println("Class represented by myClass: "
                           + myClass.toString());
  
        // Check if this class is an interface
        // using isInterface() method
        System.out.println("Is Test an interface: "
                           + myClass.isInterface());
    }
}
Output:
Class represented by myClass: class Test
Is Test an interface: false

Example 2:

tabby title=”Java”]




// Java program to demonstrate isInterface() method
  
interface T {
}
  
public class Test {
    public static void main(String[] args)
        throws ClassNotFoundException
    {
  
        // returns the Class object for this class
        Class myClass = Class.forName("T");
  
        // Check if T is an interface
        // using isInterface() method
        System.out.println("Is T an interface: "
                           + myClass.isInterface());
    }
}
Output:
Is T an interface: true

Reference: https://docs.oracle.com/javase/9/docs/api/java/lang/Class.html#isInterface–


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