Class getSuperclass() method in Java with Examples
Last Updated :
23 Jun, 2022
The getSuperclass() method of java.lang.Class class is used to get the super class of this entity. This entity can be a class, an array, an interface, etc. The method returns the super class of this entity.
Syntax:
public Class<T> getSuperclass()
Parameter: This method does not accept any parameter.
Return Value: This method returns the super class of this entity.
Below programs demonstrate the getSuperclass() method.
Example 1:
Java
public class Test {
public static void main(String[] args)
throws ClassNotFoundException
{
Class myClass = Class.forName("Test");
System.out.println("Class represented by myClass: "
+ myClass.toString());
System.out.println("Superclass of myClass: "
+ myClass.getSuperclass());
}
}
|
Example 2:
Java
public class Test {
class Arr {
}
public static void main(String[] args)
throws ClassNotFoundException
{
Class arrClass = Arr. class ;
System.out.println("Superclass of arrClass: "
+ arrClass.getSuperclass());
}
}
|
Example 3:
Java
class X{
int a;
float b;
}
class Y extends X{
double c;
}
class GFG{
public static void main(String args[]){
X x= new X();
Y y= new Y();
Class<?> clObj;
clObj=x.getClass();
System.out.println( "a is object of type: " + clObj.getName());
clObj=y.getClass();
System.out.println( "y is object of type: " + clObj.getName());
clObj=clObj.getSuperclass();
System.out.println( "y's superclass is: " + clObj.getName());
}
}
|
Output
a is object of type: X
y is object of type: Y
y's superclass is: X
Reference: https://docs.oracle.com/javase/9/docs/api/java/lang/Class.html#getSuperclass–
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