# Class 9 NCERT Solutions – Chapter 3 Coordinate Geometry – Exercise 3.3

**Question 1: In which quadrant or on which axis do each of the points (– 2, 4), (3, – 1), (– 1, 0), (1, 2) and (– 3, – 5) lie? Verify your answer by locating them on the Cartesian plane.**

**Solution: **

**(i)** The point (-2, 4) lies in II^{nd} Quadrant in the Cartesian plane as x coordinate is negative and the y coordinate is positive.

**(ii)** The point (3, -1) lies in IV^{th} Quadrant in the Cartesian plane as x coordinate is positive and the y coordinate is negative.

**(iii)** The point (-1, 0) lies on the negative x-axis and the value of x coordinate is negative.

**(iv)** The point (1, 2) lies in I^{st} Quadrant in the Cartesian as both x and y are positive.

**(v)** The point (-3,-5) lies in the III^{rd} Quadrant in the Cartesian plane as both x and y are negative.

**Question 2: Plot the points (x, y) given in the following table on the plane, choosing suitable units of distance on the axes.**

**Solution:**

We have to plot these points A(-2, 8), B(-1, 7), C(0, -1.25), D(1, 3) and E(3, -1).

Steps we have to use to plot these points,

- Let 1 unit represents 1 cm.
- To plot (-2, 8), we take (-2) units on x-axis and (+8) units on y-axis. Now we can plot A (-2, 8), it will lie in quadrant-II.
- To plot (-1, 7), we take (-1) units on x-axis and (+7) units on y-axis. Now we can plot B(-1, 7), it will lie in quadrant-II.
- To plot (0, -1.25), we will proceed (-1.25) units under the x-axis on the y-axis and mark the plot as C(0, -1.25), it will lie on the negative side of y-axis.
- To plot (1, 3), we take (+1) unit on x-axis and (+3) units on y-axis. Now we can plot D(1, 3), it will lie in quadrant-I.
- To plot (3, -1), we take (+3) units on x-axis and (-1) unit on y-axis. Now we can plot the point E(3, -1), it will lie in quadrant-IV.