# Class 9 NCERT Solutions- Chapter 14 Statistics – Exercise 14.4

• Last Updated : 25 Jan, 2021

### Find the mean, median, and mode of these scores

Solution:

Mean = Sum of all the elements/total number of elements

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Mean = (2 + 3 + 4 + 5 + 0 + 1 + 3 + 3 + 4 + 3) / 10

Mean = 2.8

Now calculating Median:

Arranging the given data in ascending order, we get,

0, 1, 2, 3, 3, 3, 3 4, 4, 5

Median = (3 + 3) / 2 = 3

For mode, we will count the element occurring the maximum number of times.

Hence, the mode is 3.

### Find the mean, median, and mode of this data.

Solution:

Mean = Sum of all the elements/total number of elements.

Mean = (41 + 39 + 48 + 52 + 46 + 62 + 54 + 40 + 96 + 52 + 98 + 40 + 42 + 50 + 60) / 15

Mean = 54.8

Now we have to find the median:

Arranging the given data in ascending order, we get,

39, 40, 40, 41, 42, 46, 48, 52, 52, 52, 54, 60, 62, 96, 98

Here the number of elements is n = 15

Thus, the middle element is the median = 52

Mode = Element 52 occurs 3 times, which is the maximum number of times.

Hence, Mode = 52

### 29, 32, 48, 50, x, x + 2, 72, 78, 84, 95

Solution:

Here, the data is already in ascending order.

Since n = 10 (an even number)

∴ Median is the average of the middlemost two elements.

Since median = 63 as given in the question

∴ (x + x + 2) / 2 = 63

∴ x = 63 – 1 = 62

Hence, the value x is 62.

### Question 4. Find the mode of 14, 25, 14, 28, 18, 17, 18, 14, 23, 22, 14, 18.

Solution:

When we arrange the data in ascending order, we get,

14, 14, 14, 14, 17, 18, 18, 18, 22, 23, 25, 28.

Since data 14 is occurring the maximum number of times.

Hence, the required mode of the given data = 14

### Question 5. Find the mean salary of 60 workers of a factory from the following table:

Solution:

Calculation table based on the given data:

Mean = (305000)/60 = 5083.33.

Thus, the required mean salary = ₹ 5083.33

### (ii) The mean is not an appropriate measure of central tendency but the median is an appropriate measure of central tendency.

Solution:

(i) Mean height of family members where all are of approximately the same height. The entries in this case will be close to each other. Therefore, the mean will be calculated as an appropriate measure of central tendency.

(ii) Median weight of a pen, a book, a Cotton Pack, a matchbox, and a Table.

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