# Class 9 NCERT Solutions- Chapter 14 Statistics – Exercise 14.4

### Question 1. The following number of goals were scored by a team in a series of 10 matches:

### 2, 3, 4, 5, 0, 1, 3, 3, 4, 3

### Find the mean, median, and mode of these scores

**Solution:**

Mean = Sum of all the elements/total number of elements

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free classeswhich will definitely help them in making a wise career choice in the future.Mean = (2 + 3 + 4 + 5 + 0 + 1 + 3 + 3 + 4 + 3) / 10

Mean = 2.8

Now calculating Median:

Arranging the given data in ascending order, we get,

0, 1, 2, 3, 3, 3, 3 4, 4, 5

Median = (3 + 3) / 2 = 3

For mode, we will count the element occurring the maximum number of times.

Hence, the mode is 3.

### Question 2. In a mathematics test given to 15 students, the following marks (out of 100) are recorded:

### 41, 39, 48, 52, 46, 62, 54, 40, 96, 52, 98, 40, 42, 52, 60

### Find the mean, median, and mode of this data.

**Solution:**

Mean = Sum of all the elements/total number of elements.

Mean = (41 + 39 + 48 + 52 + 46 + 62 + 54 + 40 + 96 + 52 + 98 + 40 + 42 + 50 + 60) / 15

Mean = 54.8

Now we have to find the median:

Arranging the given data in ascending order, we get,

39, 40, 40, 41, 42, 46, 48, 52, 52, 52, 54, 60, 62, 96, 98

Here the number of elements is n = 15

Thus, the middle element is the median = 52

Mode = Element 52 occurs 3 times, which is the maximum number of times.

Hence, Mode = 52

### Question 3. The following observations have been arranged in ascending order. If the median of the data is 63, find the value of x.

### 29, 32, 48, 50, x, x + 2, 72, 78, 84, 95

**Solution:**

Here, the data is already in ascending order.

Since n = 10 (an even number)

∴ Median is the average of the middlemost two elements.

Since median = 63 as given in the question

∴ (x + x + 2) / 2 = 63

∴ x = 63 – 1 = 62

Hence, the value x is 62.

### Question 4. Find the mode of 14, 25, 14, 28, 18, 17, 18, 14, 23, 22, 14, 18.

**Solution:**

When we arrange the data in ascending order, we get,

14, 14, 14, 14, 17, 18, 18, 18, 22, 23, 25, 28.

Since data 14 is occurring the maximum number of times.

Hence, the required mode of the given data = 14

### Question 5. Find the mean salary of 60 workers of a factory from the following table:

Salary (in ₹) | Number of workers |
---|---|

3000 | 16 |

4000 | 12 |

5000 | 10 |

6000 | 8 |

7000 | 6 |

8000 | 4 |

9000 | 3 |

10000 | 1 |

Total | 60 |

**Solution:**

Calculation table based on the given data:

Salary (in Rs.)(x_{i})

No. of workers(f_{i})

f_{i}x_{i }3000

16

3000 * 16 = 480000

4000

12

4000 * 12 = 48000

5000

10

5000 * 10 = 50000

6000

8

6000 * 8 = 48000

7000

6

7000 * 6 = 42000

8000

4

8000 * 4 = 32000

9000

3

9000 * 3 = 27000

10000

1

10000 * 1 = 10000

Total

60

305000Mean = (305000)/60 = 5083.33.

Thus, the required mean salary = ₹ 5083.33

### Question 6. Give one example of a situation in which

### (i) The mean is an appropriate measure of central tendency.

### (ii) The mean is not an appropriate measure of central tendency but the median is an appropriate measure of central tendency.

**Solution:**

(i)Mean height of family members where all are of approximately the same height. The entries in this case will be close to each other. Therefore, the mean will be calculated as an appropriate measure of central tendency.

(ii)Median weight of a pen, a book, a Cotton Pack, a matchbox, and a Table.