Class 9 NCERT Solutions – Chapter 1 Number System – Exercise 1.6
Question 1. Find the Value of:
(i) 641/2
641/2
= (8 × 8)1/2
= (82)½
= 81
= 8
(ii) 321/5
321/5
= (2 x 2 x 2 x 2 x 2)1/5
= (25)⅕
= 21
= 2
(iii) 1251/3
(125)1/3
= (5 × 5 × 5)1/3
= (53)⅓
= 51
= 5
Question 2. Find the value of:
(i) 93/2
93/2
= (3 × 3)3/2
= (32)3/2
= 33
= 27
(ii) 322/5
322/5
= (2 × 2 × 2 × 2 × 2)2/5
= (25)2⁄5
= 22
= 4
(iii) 163/4
163/4
= (2 × 2 × 2 × 2)3/4
= (24)3⁄4
= 23
= 8
(iv) 125-1/3
125-1/3
= (5 × 5 × 5)-1/3
= (53)-1⁄3
= 5-1
= 1/5
Question 3. Simplify the followings:
(i) 22/3 × 21/5
22/3 × 21/5
= 2(2/3) + (1/5) ⸪ As, am × an = am + n
= 213/15
(ii) (1/33)7
(1/33)7
= (3-3)7 ⸪ As, (am)n = am x n
= 3-21
(iii) 111/2/111/4
111/2/111/4
= 11(1/2) – (1/4) ⸪ As, am × a-n = am – n
= 111/4
(iv) 71/2 × 81/2
71/2 × 81/2
= (7 × 8)1/2 ⸪ As, am × bm = (a × b)m
= 561/2
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