# Class 8 RD Sharma- Chapter 25 Data Handling III (Pictorial Representation Of Data As Pie Charts Or Circle Graphs) – Exercise 25.2

### (ii) Expenditure incurred on labour.

Solution:

(i) Expenditure incurred on cement =  x total cost

â‡’ 112500 =  x total cost

Hence, the total cost of the flat = 540000

(ii) Expenditure incurred on labour =  x total cost

x 540000

Hence, the expenditure incurred on labour = 150000

### (i) Wheat (ii) Sugar (iii) Rice (iv) Maize (v) Gram

Solution:

We are given total production = 81000

(i) Production (in tonnes) of wheat =  x total production

x 81000

= 27000

(ii) Production (in tonnes) of sugar =  x total production

x 81000

= 22500

(iii) Production (in tonnes) of rice =  x total production

x 81000

= 13500

(iv) Production (in tonnes) of maize =  x total production

x 81000

= 6750

(v) Production (in tonnes) of gram =  x total production

x 81000

= 11250

### (ii) What is the ratio of students in science and arts?

Solution:

(i) Students admitted in Science = x total students

â‡’ 1000 =  x total students

Hence, the total number of students = 3600

(ii) Students admitted in arts =  x total students

â‡’ students admitted in arts =  x 3600

= 1200

Therefore, the ratio of students in science and arts =  = 5 : 6

### Question 4. In the following figure, the pie-chart shows the marks obtained by a student in an examination. If the student secures 440 marks in all, calculate his marks in each of the given subjects.

Solution:

We are given total marks scored by student = 440

Marks of student in Mathematics =x total marks

x 440 = 132

Marks of student in Hindi = x total marks

x 440 = 66

Marks of student in Social Science = x total marks

x 440 = 55

Marks of student in English = x total marks

x 440 = 88

Marks of student in Science = x total marks

x 440 = 99

### Question 5. In the following figure, the pie-chart shows the marks obtained by a student in various subjects. If the student scored 135 marks in mathematics, find the total marks in all the subjects. Also, find his score in individual subjects.

Solution:

Marks scored in Mathematics = x total marks

â‡’ 135 =  x total marks

â‡’ total marks scored by student = 540

Marks of student in Hindi = x total marks

x 540 = 90

Marks of student in Social Science = x total marks

x 540 = 108

Marks of student in English = x total marks

x 540 = 93

Marks of student in Science = x total marks

x 540 = 114

### (iii) What is the ratio of expenses on food and rent?

Solution:

Given, total money spent by Shikha = Rs. 16000

(i) Expenditure on rent = x total money

x 16000

Hence, the total spent on rent = 3600

(ii) Expenditure on education = x total cost

x 16000

Hence, the total spent on education = 1600

(iii) Expenditure on food = x total cost

x 16000

Hence, the total spent on food = 6000

Therefore, the ratio of expenses on food and rent = = 5 : 3

### Question 7. The pie chart (as shown in the figure) represents the amount spent on different sports by a sports club in a year. If the total money spent by the club on sports is Rs 1,08,000, find the amount spent on each sport.

Solution:

Given, total money spent by the club on sports = Rs 1,08,000

Amount spent on Tennis = x total money

x 108000

Hence, the total amount spent on Tennis = 15000

Amount spent on Hockey = x total money

x 108000

Hence, the total amount spent on Hockey = 30000

Amount spent on Football = x total money

x 108000

Hence, the total amount spent on Football = 18000

Amount spent on Cricket = x total money

x 108000

Hence, the total amount spent on Cricket = 45000

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