**Question 1: Construct the following quadrilaterals.**

**(i) Quadrilateral LIFT****LI = 4 cm****IF = 3 cm****TL = 2.5 cm****LF = 4.5 cm****IT = 4 cm**

**Solution:**

Steps of construction:

Step 1:Draw a line of 4 cm and label it as LIStep 2:Taking I as the center draw an arc of radius 3cmStep 3:Taking L as the center draw an arc of radius 4.5cm, so that both the arcs from I and L intersect each other and marks the intersection point as F. consider the fig below

Step 4:Join IF and LFStep 5:Take L as center draw an arc of radius 2.5 cmStep 6:Take I as center draw an arc of 4 cm to meet the previous arc and mark the intersection point as T.

Step 7:Join TF and TLStep 8:Hence we have the required quadrilateral LIFT.

**(ii) Quadrilateral GOLD****OL = 7.5 cm****GL = 6 cm****GD = 6 cm****LD = 5 cm****OD = 10 cm**

**Solution:**

Steps of construction:

Step 1:Draw a line OL of 7.5 cmStep 2:Taking L as the center draw an arc of 5 cm.Step 3:Taking O as the center draw an arc of 10 cm and let it intersect with the previous arc. Mark the intersection point as D as shown below:

Step 4:Join LD and OD.Step 5:Take D as the center and draw an arc of 6 cm.Step 6:Now take L as the center and drawn another arc of 6 cm that will intersect with the former arc at point G.

Step 7:Join GL and GD.Step 8:Hence we have the required quadrilateral GOLD.

**(iii) Rhombus BEND****BN = 5.6 cm****DE = 6.5 cm**

**Solution:**

Steps of construction:

Step 1:Draw a line BN of 5.6 cmStep 2:Draw perpendicular bisector of BN and mark the bisector point as O

Step 3:Draw two arcs with center O of radius1× DE =1× 6.5 cm = 3.25 cm and these arcs will meet the bisector at point D and E

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Step 4:Join BE, EN, ND, and BD.Step 5:Hence we have the required rhombus BEND.