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Class 8 NCERT Solutions – Chapter 4 Practical Geometry – Exercise 4.2
  • Last Updated : 15 Dec, 2020

Question 1: Construct the following quadrilaterals.

(i) Quadrilateral LIFT
LI = 4 cm
IF = 3 cm
TL = 2.5 cm
LF = 4.5 cm
IT = 4 cm

Solution:

Steps of construction:

Step 1: Draw a line of 4 cm and label it as LI
Step 2: Taking I as the center draw an arc of radius 3cm
Step 3: Taking L as the center draw an arc of radius 4.5cm, so that both the arcs from I and L intersect each other and marks the intersection point as F. consider the fig below 



Step 4: Join IF and LF
Step 5: Take L as center draw an arc of radius 2.5 cm
Step 6: Take I as center draw an arc of 4 cm to meet the previous arc and mark the intersection point as T.

Step 7: Join TF and TL
Step 8: Hence we have the required quadrilateral LIFT.

(ii) Quadrilateral GOLD
OL = 7.5 cm
GL = 6 cm
GD = 6 cm
LD = 5 cm
OD = 10 cm

Solution:

Steps of construction:

Step 1: Draw a line OL of 7.5 cm
Step 2: Taking L as the center draw an arc of 5 cm.
Step 3: Taking O as the center draw an arc of 10 cm and let it intersect with the previous arc. Mark the intersection point as D as shown below:



Step 4: Join LD and OD.
Step 5: Take D as the center and draw an arc of 6 cm.
Step 6: Now take L as the center and drawn another arc of 6 cm that will intersect with the former arc at point G.

Step 7: Join GL and GD.
Step 8: Hence we have the required quadrilateral GOLD.

(iii) Rhombus BEND
BN = 5.6 cm
DE = 6.5 cm

Solution:

Steps of construction:

Step 1: Draw a line BN of 5.6 cm
Step 2: Draw perpendicular bisector of BN and mark the bisector point as O

Step 3:  Draw two arcs with center O of radius  × DE =  × 6.5 cm = 3.25 cm and these arcs will meet the bisector at point D and E
                                                                            2                2

Step 4: Join BE, EN, ND, and BD.
Step 5: Hence we have the required rhombus BEND. 


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