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# Class 11 RD Sharma Solutions – Chapter 30 Derivatives – Exercise 30.5 | Set 2

• Last Updated : 30 Apr, 2021

### Question 16.

Solution:

By using quotient rule, we get,

### Question 17.

Solution:

By using quotient rule, we get,

= 10x cosec x log 10 − 10x cosec x cot x

= 10x cosec x (log 10 − cot x)

### Question 18.

Solution:

By using quotient rule, we get,

### Question 19.

Solution:

By using quotient rule, we get,

### Question 20.

Solution:

By using quotient rule, we get,

### Question 21.

Solution:

By using quotient rule, we get,

### Question 22.

Solution:

By using quotient rule, we get,

### Question 23.

Solution:

By using quotient rule, we get,

### Question 24.

Solution:

By using quotient rule, we get,

### Question 25.

Solution:

By using quotient rule, we get,

### Question 26.

Solution:

By using quotient rule, we get,

### Question 27.

Solution:

By using quotient rule, we get,

### Question 28.

Solution:

By using quotient rule, we get,

= nxn-1 cosec x − xn cot x cosec x

### Question 29.

Solution:

By using quotient rule, we get,

### Question 30.

Solution:

By using quotient rule, we get,

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