Class 11 RD Sharma Solutions – Chapter 2 Relations – Exercise 2.1
Question 1(i). If (a/3 + 1, b – 2/3) = (5/3, 1/3), find the values of a and b.
Solution:
According to the definition of equality of ordered pairs
(a/3 + 1, b – 2/3) = (5/3, 1/3)
⇒ a/3 + 1 = 5/3 and b – 2/3 =1/3
⇒ a/3 = (5 – 3)/3 and b = (1/3 + 2/3)
⇒ a/3 = 2/3 and b = 3/3
⇒ a = 2 and b = 1
Question 1(ii). If (x + 1, 1) = (3, y – 2), find the values of x and y.
Solution:
According to the definition of equality of ordered pairs
(x + 1, 1) = (3, y – 2)
⇒ x + 1 = 3 and 1 = y – 2
⇒ x = 3 – 1 and 1 + 2 = y
⇒ x = 2 and 3 = y
⇒ x = 2 and y = 3
Question 2. If the ordered pairs (x, -1) and (5, y) belong to the set {(a, b) : b = 2a – 3}, find the values of x and y.
Solution:
Given:
(x, -1) ∈ {(a, b) : b = 2a – 3}
and, (5, y) ∈ {(a, b) : b = 2a – 3}
⇒ -1 = 2 × x – 3 and y = 2 × 5 – 3
⇒ -1 = 2x – 3 and y = 10 – 3
⇒ 3 – 1 = 2x and y = 7
⇒ 2 = 2x and y = 7
⇒ x = 1 and y = 7
Question 3. If a ∈ {- 1, 2, 3, 4, 5} and b ∈ {0, 3, 6}, write the set of all ordered pairs (a, b) such that a + b = 5.
Solution:
Given: a ∈ {- 1, 2, 3, 4, 5} and b ∈ {0, 3, 6},
Now, we have to find the ordered pair (a, b) such that a + b = 5
So, the ordered pair (a, b) such that a + b = 5 are as follows
(a, b) ∈ {(- 1, 6), (2, 3), (5, 0)}
Question 4. If a ∈ {2, 4, 6, 9} and b ∈ {4, 6, 18, 27}, then form the set of all ordered pairs (a, b) such that a divides b and a<b.
Solution:
Given: a ∈ {2, 4, 6, 9} and b ∈ {4, 6, 18, 27}
Here,
2 divides 4, 6, 18 and is also less than all of them
4 divides 4 and is also less than none of them
6 divides 6, 18 and is less than 18 only
9 divides 18, 27 and is less than all of them
∴ Ordered pairs (a, b) are (2, 4), (2, 6), (2, 18), (6, 18), (9, 18) and (9, 27)
Question 5. If A = {1, 2} and B = {1, 3}, find A x B and B x A.
Solution:
Given: A = {1, 2} and B = {1, 3}
Now we have to find A x B, and B x A
A × B = {1, 2} × {1, 3}
= {(1, 1), (1, 3), (2, 1), (2, 3)}
B × A = {1, 3} × {1, 2}
= {(1, 1), (1, 2), (3, 1), (3, 2)}
Question 6. Let A = {1, 2, 3} and B = {3, 4}. Find A x B and show it graphically
Solution:
Given: A = {1, 2, 3} and B = {3, 4}
Now we have to find A x B
A x B = {1, 2, 3} × {3, 4}
= {(1, 3), (1, 4), (2, 3), (2, 4), (3, 3), (3, 4)}
To draw A x B graphically follow the following steps:
Step 1: Draw horizontal and vertical axis.
Step 2: The horizontal axis represents set A and the vertical axis represents set B.
Step 3: Now, draw dotted lines perpendicular to horizontal and vertical axes through the elements of set A and B
Step 4: Point of intersection of these perpendicular represents A × B
Question 7. If A = {1, 2, 3} and B = {2, 4}, what are A x B, B x A, A x A, B x B, and (A x B) ∩ (B x A)?
Solution:
Given:
A = {1, 2, 3} and B = {2, 4}
Now we have to find A × B, B × A, A × A, and (A × B) ∩ (B × A)
A × B = {1, 2, 3} × {2, 4}
= {(1, 2), (1, 4), (2, 2), (2, 4), (3, 2), (3, 4)}
B × A = {2, 4} × {1, 2, 3}
= {(2, 1), (2, 2), (2, 3), (4, 1), (4, 2), (4, 3)}
A × A = {1, 2, 3} × {1, 2, 3}
= {(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (2, 3), (3, 1), (3, 2), (3, 3)}
B × B = {2, 4} × {2, 4}
= {(2, 2), (2, 4), (4, 2), (4, 4)}
Intersection of two sets represents common elements of both the sets
So,
(A × B) ∩ (B × A) = {(2, 2)}
Question 8. If A and B two sets having 3 elements in common. If n(A) = 5, n(B) = 4, Find n(A × B) and n[(A × B) ∩ (B × A)]
Solution:
Given: n(A) = 5 and n(B) = 4
We know that if A and B are two finite sets, then n(A × B) = n(A) × n(B)
Therefore,
n(A × B) = 5 × 4 = 20
Now,
n[(A × B) ∩ (B × A)] = 3 × 3 = 9 -(∵ A and B have 3 common elements)
Question 9. Let A and B two sets. Show that the sets A × B and B × A has an elements in common if the sets A and B have an element in common.
Solution:
Let us considered(a, b) be an arbitrary elements of (A × B) ∩ (B × A). Then,
(a, b) ∈ (A × B) ∩ (B × A)
= (a, b) ∈ A × B and (a, b) ∈ B × A
= (a ∈ A and b ∈ B) and (a ∈ B and b ∈ A)
= (a ∈ A and a ∈ B) and (b ∈ A and b ∈ B)
= a ∈ A ∩ B and b ∈ A ∩ B
Hence, the sets A × B and B × A have an element in
common have an element in common.
Question 10. Let A and B two sets such that n(A) = 3 and n(B) = 2. If (x, 1), (y, 2), (z, 1) are in A × B, find A and B where x, y, z are distinct elements
Solution:
Since (x, 1), (y, 2), (z, 1) are elements of A × B. Therefore, x, y, z ∈ A and 1, 2 ∈ B
Given: n(A) = 3 and n(B) = 2
Therefore, x, y, z ∈ A and n(A) = 3
⇒ A = (x, y, z)
1, 2 ∈ B and n(B) = 2
⇒ B = (1, 2)
Question 11. Let A = {1, 2, 3, 4} and R = {(a, b) : a ∈ A, b ∈ A, a divides b}. Write R explicitly.
Solution:
Given: A = (1, 2, 3, 4) and, R = {(a, b) : a ∈ A, b ∈ A, a divides b}
Now, a/b stands for ‘a divides b’.
So, for the elements of the given sets, we find that 1/1, 1/2, 1/3, 1/4, 2/2, 3/3 and 4/4
Therefore,
R = {(1, 1), (1, 2), (1, 3), (1, 4), (2, 2), (2, 4), (3, 3), (4, 4)}
Question 12. If A = {-1, 1}, find A × A × A
Solution:
Given: A = {-1, 1}
So, A × A = {-1, 1} × {-1, 1}
= {(-1, -1), (-1, 1), (1, -1), (1, 1)}
Therefore, A × A × A = {-1, 1} × {(-1, -1), (-1, 1), (1, -1)(1, 1)}
= {(-1, -1, -1), (-1, -1, 1), (-1, 1, -1), (-1, 1, 1), (1, -1, -1), (1, -1, 1), (1, 1, -1), (1, 1, 1)}
Question 13. State whether each of the following statements are true or false. If the statements is false, re-write the given statement correctly:
(i) If P = {m, n} and Q = {n, m}, then P × Q = {(m, n), (n, m)}
(ii) If A and B are non-empty sets, then A × B is a non-empty set of ordered pairs (x, y) such that x ∈ B and y ∈ A.
(iii) If A = {1, 2} and B = {3, 4}, then A ∩ (B ∩ ∅) = ∅
Solution:
(i) False,
If P = {m, n} and Q = {n, m},
Then,
P × Q = {(m, n), (m, m), (n, n), (n, m)}
(ii) False,
If A and B are non-empty sets, then AB is a non-empty set of ordered pairs (x, y) such that x ∈ A and y ∈ B
(iii) True
Question 14. If A = {1, 2} form the set A × A × A
Solution:
Given: A = {1, 2}
So, A × A = {1, 2} × {1, 2}
= {(1, 1), (1, 2), (2, 1), (2, 2)}
Therefore,
A × A × A = {1, 2} × {(1, 1), (1, 2), (2, 1), (2, 2)}
= {(1, 1, 1), (1, 1, 2), (1, 2, 1), (1, 2, 2), (2, 1, 1), (2, 1, 2), (2, 2, 1), (2, 2, 2)}
Question 15 (i). If A = {1, 2, 4} and B = {1, 2, 3}, represent A × B graphically
Solution:
Given: A = {1, 2, 4} and B = {1, 2, 3}
So, A × B = {1, 2, 4} × {1, 2, 3}
= {(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (2, 3), (4, 1), (4, 2), (4, 3)}
Hence, we represent A on the horizontal line and B on vertical line.
So, the graphical representation of A × B is as shown below:
Question 15 (ii). If A = {1, 2, 4} and B = {1, 2, 3}, represent B × A graphically.
Solution:
Given: A = {1, 2, 4} and B = {1, 2, 3}
So, B × A = {1, 2, 3} × {1, 2, 4}
= {(1, 1), (1, 2), (1, 4), (2, 1), (2, 2), (2, 4), (3, 1), (3, 2), (3, 4)}
Hence, we represent B on the horizontal line and A on vertical line.
So, the graphical representation of B × A:
Question 15 (iii). If A = {1, 2, 4} and B = {1, 2, 3}, represent A × A graphically.
Solution:
Given: A = {1, 2, 4}, B = {1, 2, 3}
So, A × A = {1, 2, 4} × {1, 2, 4}
= {(1, 1), (1, 2), (1, 4), (2, 1), (2, 2), (2, 4), (4, 1), (4, 2), (4, 4)}
Graphical representation of A × A:
Question 15 (iv). If A = {1, 2, 4} and B = {1, 2, 3}, represent B × B graphically.
Solution:
Given: A = {1, 2, 4}, B = {1, 2, 3}
So, B × B = {1, 2, 3} × {1, 2, 3}
= {(1, 1), (1, 2), (1, 4), (2, 1), (2, 2), (2, 3), (3, 1), (3, 2), (3, 3)}
Graphical representation of B × B:
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