# chr() in Python

The chr() method returns a string representing a character whose Unicode code point is an integer.
Syntax:

```chr(num)
num : integer value
```
• The chr() method takes only one integer as argument.
• The range may vary from 0 to 1,1141,111(0x10FFFF in base 16).
• The chr() method returns a character whose unicode point is num, an integer.
• If an integer is passed that is outside the range then the method returns a ValueError.

Example: Suppose we want to print ‘G e e k s f o r G e e k s’.

 `# Python program to illustrate  ` `# chr() builtin function ` ` `  `print``(``chr``(``71``), ``chr``(``101``), ` `chr``(``101``), ``chr``(``107``), ` `chr``(``115``), ``chr``(``32``), ` `chr``(``102``), ``chr``(``111``), ` `chr``(``114``),``chr``(``32``), ` `chr``(``71``), ``chr``(``101``), ` `chr``(``101``), ``chr``(``107``),  ` `chr``(``115``)) `

Output:

```G e e k s   f o r   G e e k s
```

Another example :

 `# Python program to illustrate  ` `# chr() builtin function ` ` `  `numbers ``=` `[``17``, ``38``, ``79``] ` ` `  `for` `number ``in` `numbers: ` `     `  `    ``# Convert ASCII-based number to character. ` `    ``letter ``=` `chr``(number) ` `    ``print``(``"Character of ASCII value"``, number, ``"is "``, letter) `

Output:

```Character of ASCII value 17 is
Character of ASCII value 38 is  &
Character of ASCII value 79 is  O```

What happens if we give something out of range?

 `# Python program to illustrate  ` `# chr() builtin function ` `# if value given is  ` `# out of range ` ` `  `# Convert ASCII-based number to character ` `print``(``chr``(``400``)) `

Output:

```No Output
```

We wont get any output and the compiler will throw an error:

```Traceback (most recent call last):
File "/home/484c76fb455a624cc137946a244a9aa5.py", line 1, in
print(chr(400))
UnicodeEncodeError: 'ascii' codec can't encode character
'\u0190' in position 0: ordinal not in range(128)
```

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