Check whether two strings are anagrams of each other using unordered_map in C++
Write a function to check whether two given strings are an Anagram of each other or not.
An anagram of a string is another string that contains the same characters, only the order of characters can be different.
For example, “abcd” and “dabc” are an Anagram of each other.
Approach: Unordered Map can also be used to find if any two given strings are anagrams or not. The idea is to store each character of the first string in the map, with its frequency as value, and after that check for each character of the second string in the map, and if the character is found in the map, reduce its frequency value from the map. If the frequency of a character becomes 0, erase it from the map and at last if the map becomes empty, that means all the characters of the first string are there in the second string with the same number of occurrences(frequency of each character).
Implementation:
// C++ program to check whether// two strings are anagrams of// each other or not, using Hashmap #include <bits/stdc++.h>#include <unordered_map>using namespace std; // Function to check whether two strings// are an anagram of each otherbool isanagram(string s1, string s2){ int l1 = s1.length(); int l2 = s2.length(); unordered_map<char, int> m; if (l1 != l2) { return false; } for (int i = 0; i < l1; i++) { m[s1[i]]++; } for (int i = 0; i < l2; i++) { if (m.find(s2[i]) == m.end()) { return false; } else { m[s2[i]]--; if (m[s2[i]] == 0) { m.erase(s2[i]); } } } return m.size() == 0;} // Test functionvoid test(string str1, string str2){ cout << "Strings to be checked:\n" << str1 << "\n" << str2 << "\n"; if (isanagram(str1, str2)) { cout << "The two strings are" << "anagram of each other\n"; } else { cout << "The two strings are not" << " anagram of each other\n"; } cout << endl;} // Driver programint main(){ // Get the Strings string str1 = "geeksforgeeks"; string str2 = "forgeeksgeeks"; // Test the Strings test(str1, str2); // Get the Strings str1 = "geeksforgeeks"; str2 = "geeks"; // Test the Strings test(str1, str2); return 0;} |
Strings to be checked: geeksforgeeks forgeeksgeeks The two strings areanagram of each other Strings to be checked: geeksforgeeks geeks The two strings are not anagram of each other
Related articles:
- Check whether two strings are anagram of each other
- Check whether two Strings are Anagram of each other using HashMap in Java
Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready. To complete your preparation from learning a language to DS Algo and many more, please refer Complete Interview Preparation Course.
In case you wish to attend live classes with experts, please refer DSA Live Classes for Working Professionals and Competitive Programming Live for Students.
