Given two numbers **A** and **B**, the task is to check that A and B are in the golden ratio.**Golden Ratio:** Two numbers are said to be in the golden ratio if their ratio is the same as the ratio of the sum of the two numbers to the larger number. Here a > b > 0, Below is the geometric representation of the Golden ratio:

**Examples:**

Input:A = 1, B = 0.618Output:YesExplanation:These two numbers together forms Golden ratio

Input:A = 61.77, B = 38.22OutputYesExplanation:These two numbers together forms Golden ratio

**Approach:** The idea is to find two ratios and check that this ratio is equal to the Golden ratio. That is 1.618.

// Here A denotes the larger number

Below is the implementation of the above approach:

## C++

`// C++ implementation to check ` `// whether two numbers are in ` `// golden ratio with each other` `#include <bits/stdc++.h>` `using` `namespace` `std;` `// Function to check that two ` `// numbers are in golden ratio` `bool` `checkGoldenRatio(` `float` `a,` ` ` `float` `b)` `{` ` ` `// Swapping the numbers such ` ` ` `// that A contains the maximum` ` ` `// number between these numbers` ` ` `if` `(a <= b)` ` ` `{` ` ` `float` `temp = a;` ` ` `a = b;` ` ` `b = temp;` ` ` `}` ` ` `// First Ratio` ` ` `std::stringstream ratio1;` ` ` `ratio1 << std :: fixed <<` ` ` `std :: setprecision(3) <<` ` ` `(a / b);` ` ` `// Second Ratio` ` ` `std::stringstream ratio2;` ` ` `ratio2 << std :: fixed <<` ` ` `std :: setprecision(3) <<` ` ` `(a + b) / a;` ` ` `// Condition to check that two` ` ` `// numbers are in golden ratio` ` ` `if` `((ratio1.str() == ratio2.str()) &&` ` ` `ratio1.str() == ` `"1.618"` `)` ` ` `{` ` ` `cout << ` `"Yes"` `<< endl;` ` ` `return` `true` `;` ` ` `}` ` ` `else` ` ` `{` ` ` `cout << ` `"No"` `<< endl;` ` ` `return` `false` `;` ` ` `}` `}` ` ` `// Driver code` `int` `main()` `{` ` ` `float` `a = 0.618;` ` ` `float` `b = 1;` ` ` `// Function Call` ` ` `checkGoldenRatio(a, b);` ` ` `return` `0;` `}` `// This code is contributed by divyeshrabadiya07` |

## Java

`// Java implementation to check ` `// whether two numbers are in ` `// golden ratio with each other` `class` `GFG{` ` ` `// Function to check that two ` `// numbers are in golden ratio` `public` `static` `Boolean checkGoldenRatio(` `float` `a,` ` ` `float` `b)` `{` ` ` ` ` `// Swapping the numbers such ` ` ` `// that A contains the maximum` ` ` `// number between these numbers` ` ` `if` `(a <= b)` ` ` `{` ` ` `float` `temp = a;` ` ` `a = b;` ` ` `b = temp;` ` ` `}` ` ` ` ` `// First Ratio` ` ` `String ratio1 = String.format(` `"%.3f"` `, a / b);` ` ` ` ` `// Second Ratio` ` ` `String ratio2 = String.format(` `"%.3f"` `, (a + b) / a);` ` ` ` ` `// Condition to check that two` ` ` `// numbers are in golden ratio` ` ` `if` `(ratio1.equals(ratio2) &&` ` ` `ratio1.equals(` `"1.618"` `))` ` ` `{` ` ` `System.out.println(` `"Yes"` `);` ` ` `return` `true` `;` ` ` `}` ` ` `else` ` ` `{` ` ` `System.out.println(` `"No"` `); ` ` ` `return` `false` `;` ` ` `}` `}` `// Driver code` `public` `static` `void` `main(String []args)` `{` ` ` `float` `a = (` `float` `)` `0.618` `;` ` ` `float` `b = ` `1` `;` ` ` ` ` `// Function Call` ` ` `checkGoldenRatio(a, b);` `}` `}` `// This code is contributed by rag2127` |

## Python3

`# Python3 implementation to check` `# whether two numbers are in` `# golden ratio with each other` `# Function to check that two` `# numbers are in golden ratio` `def` `checkGoldenRatio(a, b):` ` ` ` ` `# Swapping the numbers such` ` ` `# that A contains the maximum` ` ` `# number between these numbers` ` ` `a, b ` `=` `max` `(a, b), ` `min` `(a, b)` ` ` ` ` `# First Ratio` ` ` `ratio1 ` `=` `round` `(a` `/` `b, ` `3` `)` ` ` ` ` `# Second Ratio` ` ` `ratio2 ` `=` `round` `((a` `+` `b)` `/` `a, ` `3` `)` ` ` `# Condition to check that two` ` ` `# numbers are in golden ratio` ` ` `if` `ratio1 ` `=` `=` `ratio2 ` `and` `\` ` ` `ratio1 ` `=` `=` `1.618` `:` ` ` `print` `(` `"Yes"` `)` ` ` `return` `True` ` ` `else` `:` ` ` `print` `(` `"No"` `)` ` ` `return` `False` ` ` `# Driver Code` `if` `__name__ ` `=` `=` `"__main__"` `:` ` ` `a ` `=` `0.618` ` ` `b ` `=` `1` ` ` ` ` `# Function Call` ` ` `checkGoldenRatio(a, b)` |

## C#

`// C# implementation to check ` `// whether two numbers are in ` `// golden ratio with each other` `using` `System;` `using` `System.Collections.Generic;` `class` `GFG {` ` ` ` ` `// Function to check that two ` ` ` `// numbers are in golden ratio` ` ` `static` `bool` `checkGoldenRatio(` `float` `a,` ` ` `float` `b)` ` ` `{` ` ` `// Swapping the numbers such ` ` ` `// that A contains the maximum` ` ` `// number between these numbers` ` ` `if` `(a <= b)` ` ` `{` ` ` `float` `temp = a;` ` ` `a = b;` ` ` `b = temp;` ` ` `}` ` ` ` ` `// First Ratio` ` ` `string` `ratio1 = String.Format(` `"{0:0.000}"` `, a / b);` ` ` ` ` `// Second Ratio` ` ` `string` `ratio2 = String.Format(` `"{0:0.000}"` `, (a + b) / a);` ` ` `// Condition to check that two` ` ` `// numbers are in golden ratio` ` ` `if` `(ratio1 == ratio2 && ratio1 == ` `"1.618"` `)` ` ` `{` ` ` `Console.WriteLine(` `"Yes"` `);` ` ` `return` `true` `;` ` ` `}` ` ` `else` ` ` `{` ` ` `Console.WriteLine(` `"No"` `);` ` ` `return` `false` `;` ` ` `}` ` ` `}` ` ` ` ` `// Driver code ` ` ` `static` `void` `Main() {` ` ` `float` `a = (` `float` `)0.618;` ` ` `float` `b = 1;` ` ` ` ` `// Function Call` ` ` `checkGoldenRatio(a, b);` ` ` `}` `}` `// This code is contributed by divyesh072019` |

**Output:**

Yes

**References:** https://en.wikipedia.org/wiki/Golden_ratio

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