 Open in App
Not now

# Check whether the sum of element of a node is equal to the given key value

• Difficulty Level : Easy
• Last Updated : 20 Sep, 2022

Given an integer k and a linked list, every node of which consists of a pair of integer variable first and second to hold the data, and a pointer pointing to the next node in the list. The task is to find whether the sum of data variables of any of the nodes is equal to k. If yes then print Yes else print No.

Examples:

Input: (1, 2) -> (2, 3) -> (3, 4) -> (4, 5) -> NULL, k = 5
Output: Yes
For the second node, the sum of data variables is 2 + 3 = 5.

Input: (1, 2) -> (2, 3) -> (3, 4) -> (4, 5) -> NULL, k = 15
Output: No

Approach: Traverse the whole linked list until the sum of elements of a node is equal to the key value. When sum of element of a node is equal to key value then print Yes. If there is no such node whose sum of element is equal to the key value then print No

Below is the implementation of the above approach:

## C++

 `// C++ implementation of the approach``#include ``using` `namespace` `std;` `// Represents node of the linked list``struct` `Node {``    ``int` `first;``    ``int` `second;``    ``Node* next;``};` `// Insertion in linked list``void` `insert(Node** head, ``int` `f, ``int` `s)``{``    ``Node* ptr = *head;``    ``Node* temp = ``new` `Node();``    ``temp->first = f;``    ``temp->second = s;``    ``temp->next = NULL;` `    ``if` `(*head == NULL)``        ``*head = temp;``    ``else` `{``        ``while` `(ptr->next != NULL)``            ``ptr = ptr->next;` `        ``ptr->next = temp;``    ``}``}` `// Function that returns true``// if the sum of element in a node = k``bool` `checkK(Node* head, ``int` `k)``{` `    ``// Check every node of the linked list``    ``while` `(head != NULL) {` `        ``// If sum of the data of the current node = k``        ``if` `((head->first + head->second) == k)``            ``return` `true``;` `        ``// Get to next node in the list``        ``head = head->next;``    ``}` `    ``// No matching node found``    ``return` `false``;``}``// Driver code``int` `main()``{``    ``Node* head = NULL;``    ``insert(&head, 1, 2);``    ``insert(&head, 2, 3);``    ``insert(&head, 3, 4);``    ``insert(&head, 4, 5);``    ``int` `k = 5;` `    ``if` `(checkK(head, k))``        ``cout << ``"Yes"``;``    ``else``        ``cout << ``"No"``;` `    ``return` `0;``}`

## Java

 `// Java implementation of the approach``class` `GfG {` `    ``// Represents node of the linked list``    ``static` `class` `Node {``        ``int` `first;``        ``int` `second;``        ``Node next;``    ``}``    ``static` `Node head = ``null``;` `    ``// Insertion in linked list``    ``static` `void` `insert(``int` `f, ``int` `s)``    ``{``        ``Node ptr = head;``        ``Node temp = ``new` `Node();``        ``temp.first = f;``        ``temp.second = s;``        ``temp.next = ``null``;` `        ``if` `(head == ``null``)``            ``head = temp;``        ``else` `{``            ``while` `(ptr.next != ``null``)``                ``ptr = ptr.next;` `            ``ptr.next = temp;``        ``}``    ``}` `    ``// Function that returns true``    ``// if the sum of element in a node = k``    ``static` `boolean` `checkK(Node head, ``int` `k)``    ``{` `        ``// Check every node of the linked list``        ``while` `(head != ``null``) {` `            ``// If sum of the data of the current node = k``            ``if` `((head.first + head.second) == k)``                ``return` `true``;` `            ``// Get to next node in the list``            ``head = head.next;``        ``}` `        ``// No matching node found``        ``return` `false``;``    ``}``    ``// Driver code``    ``public` `static` `void` `main(String[] args)``    ``{``        ``// Node* head = NULL;``        ``insert(``1``, ``2``);``        ``insert(``2``, ``3``);``        ``insert(``3``, ``4``);``        ``insert(``4``, ``5``);``        ``int` `k = ``5``;` `        ``if` `(checkK(head, k) == ``true``)``            ``System.out.println(``"Yes"``);``        ``else``            ``System.out.println(``"No"``);``    ``}``}` `// This code is contributed by Prerna Saini`

## Python3

 `# Python3 implementation of the approach`` ` `# Represents node of the linked list``class` `Node:``    ` `    ``def` `__init__(``self``):``        ` `        ``self``.first ``=` `0``        ``self``.second ``=` `0``        ``self``.``next` `=` `None` `# Insertion in linked list``def` `insert(head, f, s):` `    ``ptr ``=` `head``    ``temp ``=` `Node()``    ``temp.first ``=` `f``    ``temp.second ``=` `s``    ``temp.``next` `=` `None`` ` `    ``if` `(head ``=``=` `None``):``        ``head ``=` `temp``    ``else``:``        ``while` `(ptr.``next` `!``=` `None``):``            ``ptr ``=` `ptr.``next`` ` `        ``ptr.``next` `=` `temp``        ` `    ``return` `head``    ` `# Function that returns true``# if the sum of element in a node = k``def` `checkK(head, k):` `    ``# Check every node of the linked list``    ``while` `(head !``=` `None``):`` ` `        ``# If sum of the data of the current node = k``        ``if` `((head.first ``+` `head.second) ``=``=` `k):``            ``return` `True`` ` `        ``# Get to next node in the list``        ``head ``=` `head.``next`` ` `    ``# No matching node found``    ``return` `False` `# Driver code``if` `__name__``=``=``'__main__'``:``    ` `    ``head ``=` `None``    ``head ``=` `insert(head, ``1``, ``2``)``    ``head ``=` `insert(head, ``2``, ``3``)``    ``head ``=` `insert(head, ``3``, ``4``)``    ``head ``=` `insert(head, ``4``, ``5``)``    ``k ``=` `5`` ` `    ``if` `(checkK(head, k)):``        ``print``(``"Yes"``)``    ``else``:``        ``print``(``"No"``)`` ` `# This code is contributed by rutvik_56`

## C#

 `using` `System;` `// c# implementation of the approach``public` `class` `GfG {` `    ``// Represents node of the linked list``    ``public` `class` `Node {``        ``public` `int` `first;``        ``public` `int` `second;``        ``public` `Node next;``    ``}``    ``public` `static` `Node head = ``null``;` `    ``// Insertion in linked list``    ``public` `static` `void` `insert(``int` `f, ``int` `s)``    ``{``        ``Node ptr = head;``        ``Node temp = ``new` `Node();``        ``temp.first = f;``        ``temp.second = s;``        ``temp.next = ``null``;` `        ``if` `(head == ``null``) {``            ``head = temp;``        ``}``        ``else` `{``            ``while` `(ptr.next != ``null``) {``                ``ptr = ptr.next;``            ``}` `            ``ptr.next = temp;``        ``}``    ``}` `    ``// Function that returns true``    ``// if the sum of element in a node = k``    ``public` `static` `bool` `checkK(Node head, ``int` `k)``    ``{` `        ``// Check every node of the linked list``        ``while` `(head != ``null``) {` `            ``// If sum of the data of the current node = k``            ``if` `((head.first + head.second) == k) {``                ``return` `true``;``            ``}` `            ``// Get to next node in the list``            ``head = head.next;``        ``}` `        ``// No matching node found``        ``return` `false``;``    ``}``    ``// Driver code``    ``public` `static` `void` `Main(``string``[] args)``    ``{``        ``// Node* head = NULL;``        ``insert(1, 2);``        ``insert(2, 3);``        ``insert(3, 4);``        ``insert(4, 5);``        ``int` `k = 5;` `        ``if` `(checkK(head, k) == ``true``) {``            ``Console.WriteLine(``"Yes"``);``        ``}``        ``else` `{``            ``Console.WriteLine(``"No"``);``        ``}``    ``}``}`

## Javascript

 ``

Output:

`Yes`

Time Complexity: O(N), where N is the number of nodes in the linked list.
Auxiliary Space: O(1), as constant space is being used.

My Personal Notes arrow_drop_up