Check whether the given floating point number is a palindrome
Given a floating point number N, the task is to check whether it is palindrome or not.
Input: N = 123.321
Output: YesInput: N = 122.1
Output: Yes
Approach:
- First convert the given floating point number into a character array.
- Initialize the low to first index and high to last index.
- While low < high:
- If character at low is not equal to the character at high then exit and print “No”.
- If character at low is equal to the character at high then continue after incrementing low and decrementing high..
- If the above loop completes successfully then print “Yes”.
Below is the implementation of the above approach:
C++
// C++ implementation of the approach #include <bits/stdc++.h> using namespace std; // Function that returns true if num is palindrome bool isPalindrome(float num) { // Convert the given floating point number // into a string stringstream ss; ss << num; string s; ss >> s; // Pointers pointing to the first and // the last character of the string int low = 0; int high = s.size() - 1; while (low < high) { // Not a palindrome if (s[low] != s[high]) return false; // Update the pointers low++; high--; } return true; } // Driver code int main() { float n = 123.321f; if (isPalindrome(n)) cout << "Yes"; else cout << "No"; return 0; } // This code is contributed by Rajput-Ji |
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Java
// Java implementation of the approach public class GFG { // Function that returns true if num is palindrome public static boolean isPalindrome(float num) { // Convert the given floating point number // into a string String s = String.valueOf(num); // Pointers pointing to the first and // the last character of the string int low = 0; int high = s.length() - 1; while (low < high) { // Not a palindrome if (s.charAt(low) != s.charAt(high)) return false; // Update the pointers low++; high--; } return true; } // Driver code public static void main(String args[]) { float n = 123.321f; if (isPalindrome(n)) System.out.print("Yes"); else System.out.print("No"); } } |
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Python3
# Python3 implementation of the approach # Function that returns true if num is palindrome def isPalindrome(num) : # Convert the given floating point number # into a string s = str(num) # Pointers pointing to the first and # the last character of the string low = 0 high = len(s) - 1 while (low < high): # Not a palindrome if (s[low] != s[high]): return False # Update the pointers low += 1 high -= 1 return True # Driver code n = 123.321 if (isPalindrome(n)): print("Yes") else: print("No") # This code is contributed by ihritik |
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C#
// C# implementation of the approach using System; class GFG { // Function that returns true // if num is palindrome public static bool isPalindrome(float num) { // Convert the given floating point number // into a string string s = num.ToString(); // Pointers pointing to the first and // the last character of the string int low = 0; int high = s.Length - 1; while (low < high) { // Not a palindrome if (s[low] != s[high]) return false; // Update the pointers low++; high--; } return true; } // Driver code public static void Main() { float n = 123.321f; if (isPalindrome(n)) Console.WriteLine("Yes"); else Console.WriteLine("No"); } } // This code is contributed by AnkitRai01 |
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Output:
Yes
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