Skip to content
Related Articles

Related Articles

Improve Article

Check whether the given floating point number is a palindrome

  • Difficulty Level : Medium
  • Last Updated : 17 May, 2021

Given a floating-point number N, the task is to check whether it is palindrome or not. 

Input: N = 123.321 
Output: Yes
Input: N = 122.1 
Output: No  

Approach: 

  • First, convert the given floating-point number into a character array.
  • Initialize the low to first index and high to the last index.
  • While low < high: 
    • If the character at low is not equal to the character at high then exit and print “No”.
    • If the character at low is equal to the character at high then continue after incrementing low and decrementing high…
  • If the above loop completes successfully then print “Yes”.

Below is the implementation of the above approach: 

C++




// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;
 
// Function that returns true if num is palindrome
bool isPalindrome(float num)
{
     
    // Convert the given floating point number
    // into a string
    stringstream ss;
    ss << num;
    string s;
    ss >> s;
     
    // Pointers pointing to the first and
    // the last character of the string
    int low = 0;
    int high = s.size() - 1;
 
    while (low < high)
    {
 
        // Not a palindrome
        if (s[low] != s[high])
            return false;
 
        // Update the pointers
        low++;
        high--;
    }
    return true;
}
 
// Driver code
int main()
{
    float n = 123.321f;
 
    if (isPalindrome(n))
        cout << "Yes";
    else
        cout << "No";
 
    return 0;
}
 
// This code is contributed by Rajput-Ji

Java




// Java implementation of the approach
public class GFG {
 
    // Function that returns true if num is palindrome
    public static boolean isPalindrome(float num)
    {
 
        // Convert the given floating point number
        // into a string
        String s = String.valueOf(num);
 
        // Pointers pointing to the first and
        // the last character of the string
        int low = 0;
        int high = s.length() - 1;
 
        while (low < high) {
 
            // Not a palindrome
            if (s.charAt(low) != s.charAt(high))
                return false;
 
            // Update the pointers
            low++;
            high--;
        }
 
        return true;
    }
 
    // Driver code
    public static void main(String args[])
    {
 
        float n = 123.321f;
 
        if (isPalindrome(n))
            System.out.print("Yes");
 
        else
            System.out.print("No");
    }
}

Python3




# Python3 implementation of the approach
 
# Function that returns true if num is palindrome
def isPalindrome(num) :
 
    # Convert the given floating point number
    # into a string
    s = str(num)
     
    # Pointers pointing to the first and
    # the last character of the string
    low = 0
    high = len(s) - 1
 
    while (low < high):
     
        # Not a palindrome
        if (s[low] != s[high]):
            return False
 
        # Update the pointers
        low += 1
        high -= 1
     
    return True
 
# Driver code
n = 123.321
 
if (isPalindrome(n)):
    print("Yes")
else:
    print("No")
 
# This code is contributed by ihritik

C#




// C# implementation of the approach
using System;
 
class GFG
{
 
    // Function that returns true
    // if num is palindrome
    public static bool isPalindrome(float num)
    {
 
        // Convert the given floating point number
        // into a string
        string s = num.ToString();
 
        // Pointers pointing to the first and
        // the last character of the string
        int low = 0;
        int high = s.Length - 1;
 
        while (low < high)
        {
 
            // Not a palindrome
            if (s[low] != s[high])
                return false;
 
            // Update the pointers
            low++;
            high--;
        }
        return true;
    }
 
    // Driver code
    public static void Main()
    {
        float n = 123.321f;
 
        if (isPalindrome(n))
            Console.WriteLine("Yes");
 
        else
            Console.WriteLine("No");
    }
}
 
// This code is contributed by AnkitRai01

Javascript




<script>
 
 
// Javascript implementation of the approach
 
// Function that returns true if num is palindrome
function isPalindrome(num)
{
     
    // Convert the given floating point number
    // into a string
    var s = num.toString();
     
    // Pointers pointing to the first and
    // the last character of the string
    var low = 0;
    var high = s.length - 1;
 
    while (low < high)
    {
 
        // Not a palindrome
        if (s[low] != s[high])
            return false;
 
        // Update the pointers
        low++;
        high--;
    }
    return true;
}
 
// Driver code
var n = 123.321;
if (isPalindrome(n))
    document.write( "Yes");
else
    document.write( "No");
</script>
Output: 
Yes

 

Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready.  To complete your preparation from learning a language to DS Algo and many more,  please refer Complete Interview Preparation Course.

In case you wish to attend live classes with experts, please refer DSA Live Classes for Working Professionals and Competitive Programming Live for Students.




My Personal Notes arrow_drop_up
Recommended Articles
Page :