Check whether the binary equivalent of a number ends with given string or not

Given a positive integer N, the task is to check whether the binary equivalent of that integer ends with a given string str or not. 
Print “Yes” if it ends in “str”. Otherwise, Print “No”.

Input: N = 23, str = “111”
Output: Yes
Binary of 23 = 10111, which ends with “111”

Input: N = 5, str = “111”
Output: No


Approach: The idea is to find the Binary Equivalent of N and check if str is a Suffix of its Binary Equivalent.

Below is the implementation of above approach: 






// C++ implementation of the
// above approach
#include <bits/stdc++.h>
using namespace std;
// Function returns true if
// s1 is suffix of s2
bool isSuffix(string s1, string s2)
    int n1 = s1.length();
    int n2 = s2.length();
    if (n1 > n2)
        return false;
    for (int i = 0; i < n1; i++)
        if (s1[n1 - i - 1] != s2[n2 - i - 1])
            return false;
    return true;
// Function to check if binary equivalent
// of a number ends in "111" or not
bool CheckBinaryEquivalent(int N, string str)
    // To store the binary
    // number
    int B_Number = 0;
    int cnt = 0;
    while (N != 0) {
        int rem = N % 2;
        int c = pow(10, cnt);
        B_Number += rem * c;
        N /= 2;
        // Count used to store
        // exponent value
    string bin = to_string(B_Number);
    return isSuffix(str, bin);
// Driver code
int main()
    int N = 23;
    string str = "111";
    if (CheckBinaryEquivalent(N, str))
        cout << "Yes";
        cout << "No";
    return 0;




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