Check whether BST contains Dead End or not
Given a Binary search Tree that contains positive integer values greater than 0. The task is to check whether the BST contains a dead end or not. Here Dead End means, we are not able to insert any element after that node.
Examples:
Input : 8
/ \
5 9
/ \
2 7
/
1
Output : Yes
Explanation : Node "1" is the dead End because
after that we cant insert any element.
Input : 8
/ \
7 10
/ / \
2 9 13
Output : Yes
Explanation : We can't insert any element at
node 9. If we take a closer look at the problem, we can notice that we basically need to check if there is a leaf node with value x such that x+1 and x-1 exist in BST with the exception of x = 1. For x = 1, we can’t insert 0 as the problem statement says BST contains positive integers only.
To implement the above idea we first traverse the whole BST and store all nodes in a set. We also store all leaves in a separate hash to avoid re-traversal of BST. Finally, we check for every leaf node x, if x-1 and x+1 are present in set or not.
Below is a C++ implementation of the above idea.
C++
// C++ program check weather BST contains// dead end or not#include<bits/stdc++.h>using namespace std;// A BST nodestruct Node{ int data; struct Node *left, *right;};// A utility function to create a new nodeNode *newNode(int data){ Node *temp = new Node; temp->data = data; temp->left = temp->right = NULL; return temp;}/* A utility function to insert a new Node with given key in BST */struct Node* insert(struct Node* node, int key){ /* If the tree is empty, return a new Node */ if (node == NULL) return newNode(key); /* Otherwise, recur down the tree */ if (key < node->data) node->left = insert(node->left, key); else if (key > node->data) node->right = insert(node->right, key); /* return the (unchanged) Node pointer */ return node;}// Function to store all node of given binary search treevoid storeNodes(Node * root, unordered_set<int> &all_nodes, unordered_set<int> &leaf_nodes){ if (root == NULL) return ; // store all node of binary search tree all_nodes.insert(root->data); // store leaf node in leaf_hash if (root->left==NULL && root->right==NULL) { leaf_nodes.insert(root->data); return ; } // recur call rest tree storeNodes(root-> left, all_nodes, leaf_nodes); storeNodes(root->right, all_nodes, leaf_nodes);}// Returns true if there is a dead end in tree,// else false.bool isDeadEnd(Node *root){ // Base case if (root == NULL) return false ; // create two empty hash sets that store all // BST elements and leaf nodes respectively. unordered_set<int> all_nodes, leaf_nodes; // insert 0 in 'all_nodes' for handle case // if bst contain value 1 all_nodes.insert(0); // Call storeNodes function to store all BST Node storeNodes(root, all_nodes, leaf_nodes); // Traversal leaf node and check Tree contain // continuous sequence of // size tree or Not for (auto i = leaf_nodes.begin() ; i != leaf_nodes.end(); i++) { int x = (*i); // Here we check first and last element of // continuous sequence that are x-1 & x+1 if (all_nodes.find(x+1) != all_nodes.end() && all_nodes.find(x-1) != all_nodes.end()) return true; } return false ;}// Driver programint main(){/* 8 / \ 5 11 / \ 2 7 \ 3 \ 4 */ Node *root = NULL; root = insert(root, 8); root = insert(root, 5); root = insert(root, 2); root = insert(root, 3); root = insert(root, 7); root = insert(root, 11); root = insert(root, 4); if (isDeadEnd(root) == true) cout << "Yes " << endl; else cout << "No " << endl; return 0;} |
Python3
# Python 3 program check# weather BST contains# dead end or notall_nodes = set()leaf_nodes = set()# A BST nodeclass newNode: def __init__(self, data): self.data = data self.left = None self.right = None''' A utility function to insert a new Node with given key in BST '''def insert(node, key): '''/* If the tree is empty, return a new Node */ ''' if (node == None): return newNode(key) # Otherwise, recur down # the tree if (key < node.data): node.left = insert(node.left, key) elif (key > node.data): node.right = insert(node.right, key) # return the (unchanged) # Node pointer return node# Function to store all node# of given binary search treedef storeNodes(root): global all_nodes global leaf_nodes if (root == None): return # store all node of binary # search tree all_nodes.add(root.data) # store leaf node in leaf_hash if (root.left == None and root.right == None): leaf_nodes.add(root.data) return # recur call rest tree storeNodes(root. left) storeNodes(root.right)# Returns true if there is# a dead end in tree,# else false.def isDeadEnd(root): global all_nodes global leaf_nodes # Base case if (root == None): return False # create two empty hash # sets that store all BST # elements and leaf nodes # respectively. # insert 0 in 'all_nodes' # for handle case if bst # contain value 1 all_nodes.add(0) # Call storeNodes function # to store all BST Node storeNodes(root) # Traversal leaf node and # check Tree contain # continuous sequence of # size tree or Not for x in leaf_nodes: # Here we check first and # last element of continuous # sequence that are x-1 & x+1 if ((x + 1) in all_nodes and (x - 1) in all_nodes): return True return False# Driver codeif __name__ == '__main__': '''/* 8 / \ 5 11 / \ 2 7 \ 3 \ 4 */ ''' root = None root = insert(root, 8) root = insert(root, 5) root = insert(root, 2) root = insert(root, 3) root = insert(root, 7) root = insert(root, 11) root = insert(root, 4) if(isDeadEnd(root) == True): print("Yes") else: print("No")# This code is contributed by bgangwar59 |
Output:
Yes
Time Complexity : O(n)
Simple Recursive solution to check whether BST contains dead End
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