Given a string of two characters and n distinct words of two characters. The task is to find if it is possible to arrange given words in such a way that the concatenated string has the given two character string as a substring. We can append a word multiple times.
Examples:
Input : str = "ya"
words[] = {"ah", "oy", "to", "ha"}
Output : YES
We can join "oy" and then "ah", and
then "ha" to form the string "oyahha"
which contains the string "ya".
So, the answer is "YES"
Input : str[] = "ha"
words[] = "ah"
Output :YES
The string "ahah" contains "ha"
as a substring.
Input : str = "hp"
words[] = {"ht", "tp"|
Output :NO
We can't produce a string containing
"hp" as a sub-string. Note that we
can join "ht" and then "tp" producing
"http", but it doesn't contain the
"hp" as a sub-string.
If we look at the given examples carefully, we can see that our answer will be “YES” if any of the following conditions is true,
- str is equal to any one of the N words
- str is equal to reverse of any of the words.
- It first letter of str is equal to last letter of any of the given N strings and last letter is equal to the first letter of any of the given N strings.
Otherwise our output will always be NO.
Below is the implementation of the above approach.
C++
// CPP code to check if a two character string can // be made using given strings #include <bits/stdc++.h> using namespace std; // Function to check if str can be made using // given words bool makeAndCheckString(vector<string> words, string str) { int n = words.size(); bool first = false, second = false; for (int i = 0; i < n; i++) { // If str itself is present if (words[i] == str) return true; // Match first character of str // with second of word and vice versa if (str[0] == words[i][1]) first = true; if (str[1] == words[i][0]) second = true; // If both characters found. if (first && second) return true; } return false; } // Driver Code int main() { string str = "ya"; vector<string> words = { "ah", "oy", "to", "ha"}; if (makeAndCheckString(words, str)) cout << "Yes"; else cout << "No"; return 0; } |
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Java
// Java code to check if a two character string can // be made using given strings import java.util.*; class GFG { // Function to check if str can be made using // given words static boolean makeAndCheckString(Vector<String> words, String str) { int n = words.size(); boolean first = false, second = false; for (int i = 0; i < n; i++) { // If str itself is present if (words.get(i) == str) return true; // Match first character of str // with second of word and vice versa if (str.charAt(0) == words.get(i).charAt(1)) first = true; if (str.charAt(1) == words.get(i).charAt(0)) second = true; // If both characters found. if (first && second) return true; } return false; } // Driver Code public static void main(String[] args) { String str = "ya"; String[] array = { "ah", "oy", "to", "ha"}; Vector<String> words = new Vector<String>(Arrays.asList(array)); if (makeAndCheckString(words, str)) System.out.println("Yes"); else System.out.println("No"); } } // This code is contributed by 29AjayKumar |
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Python3
# Python3 code to check if a two character string can # be made using given strings # Function to check if str can be made using # given words def makeAndCheckString(words, str): n = len(words) first = second = False for i in range(n): # If str itself is present if words[i]==str: return True # Match first character of str # with second of word and vice versa if str[0] == words[i][1]: first = True if str[1] == words[i][0]: second = True # If both characters found. if first and second: return True return False # Driver Code str = 'ya'words = ['ah', 'oy', 'to', 'ha'] if makeAndCheckString(words, str): print('YES') else: print('NO') # This code is contributed # by SamyuktaSHegde |
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C#
// C# code to check if a two character string can // be made using given strings using System; using System.Collections.Generic; class GFG { // Function to check if str can be made using // given words static bool makeAndCheckString(List<String> words, String str) { int n = words.Count; bool first = false, second = false; for (int i = 0; i < n; i++) { // If str itself is present if (words[i] == str) return true; // Match first character of str // with second of word and vice versa if (str[0] == words[i][1]) first = true; if (str[1] == words[i][0]) second = true; // If both characters found. if (first && second) return true; } return false; } // Driver Code public static void Main(String[] args) { String str = "ya"; String[] array = { "ah", "oy", "to", "ha"}; List<String> words = new List<String>(array); if (makeAndCheckString(words, str)) Console.WriteLine("Yes"); else Console.WriteLine("No"); } } // This code is contributed by Princi Singh |
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PHP
<?php // PHP code to check if a two character string can // be made using given strings // Function to check if str can be made using // given words function makeAndCheckString($words, $str) { $n = sizeof($words) ; $first = false ; $second = false; for ($i = 0; $i < $n; $i++) { // If str itself is present if ($words[$i] == $str) return true; // Match first character of str // with second of word and vice versa if ($str[0] == $words[$i][1]) $first = true; if ($str[1] == $words[$i][0]) $second = true; // If both characters found. if ($first && $second) return true; } return false; } // Driver Code $str = "ya"; $words = array( "ah", "oy", "to", "ha") ; if (makeAndCheckString($words, $str)) echo "Yes"; else echo "No"; // This code is contributed by Ryuga ?> |
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Output:
YES
This article is contributed by Sarthak Kohli. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
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