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Check if a large number is divisible by 20

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  • Difficulty Level : Easy
  • Last Updated : 25 Sep, 2022
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Given a number, the task is to check if number is divisible by 20. The input number may be large and it may not be possible to store long long int and it may be very large number then we use the string.
Examples: 
 

Input : 7575680
Output : Yes

Input : 987985865687690
Output : No

 

A number is divisible by 20 if it is divisible by 5 and 4. We can check if a number is divisible by 4 by checking if last two digits are divisible by 4. We can check for divisibility by 5 by checking last digit. Also, if the last digit of a number is zero and the second last digit is a multiple of 2 then the number is divisible by 20. 
 

C++




// CPP program to check if a large number
// is divisible by 20.
#include <iostream>
using namespace std;
 
bool divisibleBy20(string num)
{
    // Get number with last two digits
    int lastTwoDigits = stoi(num.substr(num.length() - 2,
                            num.length() - 1));
 
    // Check if the number formed by last two
    // digits is divisible by 5 and 4.
    return ((lastTwoDigits % 5 == 0) &&
            (lastTwoDigits % 4 == 0));
}
 
int main()
{
    string num = "63284689320";
    if (divisibleBy20(num))
        cout << "Yes" << endl;
    else
        cout << "No" << endl;
    return 0;
}

Java




// Java program to check if a large n
// number is divisible by 20.
import java.io.*;
 
class GFG {
     
    static Boolean divisibleBy20(String num)
    {
        // Get number with last two digits
        int lastTwoDigits = Integer.parseInt(num.substring(num.length() - 2,
                                                           num.length() ));
         
        // Check if the number formed by last two
        // digits is divisible by 5 and 4.
        return ((lastTwoDigits % 5 == 0) &&
                (lastTwoDigits % 4 == 0));
    }
     
    // Driver Program
    public static void main (String[] args)
    {
        String num = "63284689320";
        if (divisibleBy20(num) == true)
            System.out.println("Yes");
        else
            System.out.println("No");
         
    }
}
 
// This code is contributed by Gitanjali.

Python3




# Python3 program to check if a large
# number is divisible by 20.
import math
 
def divisibleBy20(num):
 
    # Get number with last two digits
    lastTwoDigits = int(num[-2:])
 
    # Check if the number formed by last two
    # digits is divisible by 5 and 4.
    return ((lastTwoDigits % 5 == 0 and
             lastTwoDigits % 4 == 0))
 
# driver code
num = "63284689320"
if (divisibleBy20(num) == True):
    print("Yes")
else:
    print("No")
 
# This code is contributed by Gitanjali.

C#




// C# program to check if a large
// 'n' number is divisible by 20.
using System;
using System.Text;
 
class GFG
{
 
static bool divisibleBy20(String num)
{
    // Get number with last two digits
    int lastTwoDigits = Int32.Parse(num.Substring(2));
     
    // Check if the number formed
    // by last two digits is
    // divisible by 5 and 4.
    return ((lastTwoDigits % 5 == 0) &&
            (lastTwoDigits % 4 == 0));
}
 
// Driver Code
static public void Main ()
{
    String num = "63284689320";
    if (divisibleBy20(num) == true)
        Console.Write("Yes");
    else
        Console.Write("No");
}
}
 
// This code is contributed by Raj

PHP




<?php
// PHP program to check
// if a large number is
// divisible by 20.
 
function divisibleBy20($num)
{
    // Get number with
    // last two digits
    $lastTwoDigits = intval(substr($num,
                           (strlen($num) - 2), 2));
 
    // Check if the number
    // formed by last two
    // digits is divisible
    // by 5 and 4.
    return (($lastTwoDigits % 5 == 0) &&
            ($lastTwoDigits % 4 == 0));
}
 
// Driver Code
$num = "63284689320";
if (divisibleBy20($num))
    echo "Yes";
else
    echo "No";
 
// This code is contributed by mits.
?>

Javascript




<script>
// Javascript program to check
// if a large number is
// divisible by 20.
function divisibleBy20(num)
{
 
    // Get number with
    // last two digits
    let lastTwoDigits = parseInt(num.slice(-2, num.length))
    console.log(num.slice(-2, 1))
 
    // Check if the number
    // formed by last two
    // digits is divisible
    // by 5 and 4.
    return ((lastTwoDigits % 5 == 0) &&
            (lastTwoDigits % 4 == 0))
}
 
// Driver Code
let num = "63284689320";
if (divisibleBy20(num))
    document.write("Yes");
else
    document.write("No");
 
// This code is contributed by _saurabh_jaiswal.
</script>

Output

Yes

Time complexity: O(1) 
Auxiliary space: O(1)

Method: Checking given number is divisible by 20 or not by using modulo division operator “%”.  

C++




#include <iostream>
using namespace std;
 
int main() {
  
    // input number
    long int num = 987985865687690;
 
    // finding given number is divisible by 20 or not
    if (num % 20 == 0) {
      cout<<"Yes";
    }
    else {
      cout<<"No";
    }
     
    return 0;
}
 
// This code is contributed by laxmigangarajula03

Java




// Java code for the above approach
// To check whether the given number is divisible by 20 or
// not
import java.math.BigInteger;
 
class GFG {
 
  public static void main(String[] args)
  {
    // input number
    BigInteger num = new BigInteger("987985865687690");
 
    // finding given number is divisible by 20 or not
    if (num.mod(new BigInteger("20"))
        .equals(new BigInteger("0"))) {
      System.out.println("Yes");
    }
    else {
      System.out.println("No");
    }
  }
}
 
// This code is contributed by phasing17

Python3




# Python code
# To check whether the given number is divisible by 20 or not
 
#input
n=987985865687690
# the above input can also be given as n=input() -> taking input from user
# finding given number is divisible by 20 or not
if int(n)%20==0:
  print("Yes")
else:
  print("No")
   
  # this code is contributed by gangarajula laxmi

C#




// C# code for the above approach
// To check whether the given number is divisible by 20 or
// not
using System;
 
public class GFG {
 
  static public void Main()
  {
    // input number
    long num = 987985865687690;
 
    // finding given number is divisible by 20 or not
    if (num % 20 == 0) {
      Console.Write("Yes");
    }
    else {
      Console.Write("No");
    }
  }
}
 
// This code is contributed by laxmigangarajula03

Javascript




<script>
       // JavaScript code for the above approach
 
       // To check whether the given number is divisible by 20 or not
 
       //input
       var n = 987985865687690
       // the above input can also be given as n=input() -> taking input from user
       // finding given number is divisible by 20 or not
       if (n % 20 == 0)
           document.write("Yes")
       else
           document.write("No")
 
 
   // This code is contributed by Potta Lokesh
   </script>

PHP




<?php
// PHP program to check
// if a large number is
// divisible by 20.
 
  // Driver Code
  // input number
$num = 987985865687690;
 
// finding given number is divisible by 20 or not
if ( ($num) % 20 == 0)
    echo "Yes";
else
    echo "No";
 
// This code is contributed by satwik4409.
?>

Output

No

Time complexity: O(1) it is performing constant operations

Auxiliary space: O(1)


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