Check if a large number is divisible by 13 or not
Given a large number, the task is to check if number is divisible by 13 or not.
Examples :
Input : 637 Output : 637 is divisible by 13. Input : 920 Output : 920 is not divisible by 13. Input : 83959092724 Output : 83959092724 is divisible by 13.
If given number num is small, we can easily find whether it is divisible by 13 or not by doing num % 13 and checking whether the result is 0 or not. But what about very large numbers. Let’s discuss for large numbers.
Below are some interesting facts about divisibility of 13.
- A number is divisible by 13 if and if alternating sum (alternatively adding and subtracting) of blocks of three from right to left is divisible by 13. For example 2911285 is divisible by 13 because alternating sum of blocks of size 3 is 2 – 911 + 285 = -650 which is divisible by 13.
- A number is divisible by 13 if and only if the number obtained by adding last digit multiplied by 4 to rest is also divisible by 13.
For example consider 2353. Applying above rule, we get 235 + 3*4 = 247. Again we apply rule and get, 24 + 7*4 = 52. Since 52 is divisible by 13, given number is divisible by 13.
Below is implementation based one first fact above (Finding alternating sum of blocks of size 3)
C++
// CPP program to check // whether a number is // divisible by 13 or not. #include <iostream> using namespace std; // Returns true if number // is divisible by 13 else // returns false bool checkDivisibility(string num) { int length = num.size(); if (length == 1 && num[0] == '0' ) return true ; // Append required 0s . // at the beginning. if (length % 3 == 1) { // Same as strcat(num, "00"); // in c. num += "00" ; length += 2; } else if (length % 3 == 2) { // Same as strcat(num, "0"); // in c. num += "0" ; length += 1; } // Alternatively add/subtract // digits in group of three // to result. int sum = 0, p = 1; for ( int i = length - 1; i >= 0; i--) { // Store group of three // numbers in group variable. int group = 0; group += num[i--] - '0' ; group += (num[i--] - '0' ) * 10; group += (num[i] - '0' ) * 100; sum = sum + group * p; // Generate alternate series // of plus and minus p *= (-1); } sum = abs (sum); return (sum % 13 == 0); } // Driver code int main() { string number = "83959092724" ; if (checkDivisibility(number)) cout << number << " is divisible by 13." ; else cout << number << " is not divisibe by 13." ; return 0; } |
Java
// Java program to check // whether a number is // divisible by 13 or not. class GFG { // Returns true if number // is divisible by 13 else // returns false static boolean checkDivisibility(String num) { int length = num.length(); if (length == 1 && num.charAt( 0 ) == '0' ) return true ; // Append required 0s . // at the beginning. if (length % 3 == 1 ) { // Same as strcat(num, "00"); // in c. num += "00" ; length += 2 ; } else if (length % 3 == 2 ) { // Same as strcat(num, "0"); // in c. num += "0" ; length += 1 ; } // Alternatively add/subtract // digits in group of three // to result. int sum = 0 , p = 1 ; for ( int i = length - 1 ; i >= 0 ; i--) { // Store group of three // numbers in group variable. int group = 0 ; group += num.charAt(i--) - '0' ; group += (num.charAt(i--) - '0' ) * 10 ; group += (num.charAt(i) - '0' ) * 100 ; sum = sum + group * p; // Generate alternate series // of plus and minus p *= (- 1 ); } sum = Math.abs(sum); return (sum % 13 == 0 ); } // Driver code public static void main(String[] args) { String number = "83959092724" ; if (checkDivisibility(number)) System.out.println(number + " is divisible by 13." ); else System.out.println(number + " is not divisibe by 13." ); } } // This code is contributed by mits |
Python 3
# Python 3 program to check whether a # number is divisible by 13 or not # Returns true if number is divisible # by 13 else returns false def checkDivisibility( num): length = len (num) if (length = = 1 and num[ 0 ] = = '0' ): return True # Append required 0s at the beginning. if (length % 3 = = 1 ): # Same as strcat(num, "00"); # in c. num = str (num) + "00" length + = 2 elif (length % 3 = = 2 ): # Same as strcat(num, "0"); # in c. num = str (num) + "0" length + = 1 # Alternatively add/subtract digits # in group of three to result. sum = 0 p = 1 for i in range (length - 1 , - 1 , - 1 ) : # Store group of three # numbers in group variable. group = 0 group + = ord (num[i]) - ord ( '0' ) i - = 1 group + = ( ord (num[i]) - ord ( '0' )) * 10 i - = 1 group + = ( ord (num[i]) - ord ( '0' )) * 100 sum = sum + group * p # Generate alternate series # of plus and minus p * = ( - 1 ) sum = abs ( sum ) return ( sum % 13 = = 0 ) # Driver code if __name__ = = "__main__" : number = "83959092724" if (checkDivisibility(number)): print ( number , "is divisible by 13." ) else : print ( number , "is not divisibe by 13." ) # This code is contributed by ChitraNayal |
C#
// C# program to check // whether a number is // divisible by 13 or not. using System; class GFG { // Returns true if number // is divisible by 13 else // returns false static bool checkDivisibility( string num) { int length = num.Length; if (length == 1 && num[0] == '0' ) return true ; // Append required 0s . // at the beginning. if (length % 3 == 1) { // Same as strcat(num, "00"); // in c. num += "00" ; length += 2; } else if (length % 3 == 2) { // Same as strcat(num, "0"); // in c. num += "0" ; length += 1; } // Alternatively add/subtract // digits in group of three // to result. int sum = 0, p = 1; for ( int i = length - 1; i >= 0; i--) { // Store group of three // numbers in group variable. int group = 0; group += num[i--] - '0' ; group += (num[i--] - '0' ) * 10; group += (num[i] - '0' ) * 100; sum = sum + group * p; // Generate alternate series // of plus and minus p *= (-1); } sum = Math.Abs(sum); return (sum % 13 == 0); } // Driver code static void Main() { string number = "83959092724" ; if (checkDivisibility(number)) Console.Write( number + " is divisible by 13." ); else Console.Write( number + " is not divisibe by 13." ); } } // This code is contributed by Sam007 |
PHP
<?php // PHP program to check // whether a number is // divisible by 13 or not. // Returns true if number // is divisible by 13 else // returns false function checkDivisibility( $num ) { $length = strlen ( $num ); if ( $length == 1 && $num [0] == '0' ) return true; // Append required 0s // at the beginning. if ( $length % 3 == 1) { // Same as strcat(num, "00"); // in c. $num += "00" ; $length += 2; } else if ( $length % 3 == 2) { // Same as strcat(num, "0"); // in c. $num += "0" ; $length += 1; } // Alternatively add/subtract // digits in group of three // to result. $sum = 0; $p = 1; for ( $i = $length - 1; $i >= 0; $i --) { // Store group of three // numbers in group variable. $group = 0; $group += $num [ $i --] - '0' ; $group += ( $num [ $i --] - '0' ) * 10; $group += ( $num [ $i ] - '0' ) * 100; $sum = $sum + $group * $p ; // Generate alternate series // of plus and minus $p *= (-1); } $sum = abs ( $sum ); return ( $sum % 13 == 0); } // Driver code $number = "83959092724" ; if (checkDivisibility( $number )) echo ( $number . " is divisible by 13." ); else echo ( $number . " is not divisibe by 13." ); // This code is contributed by Ajit. ?> |
Output :
83959092724 is divisible by 13.
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