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# Check if a large number is divisibility by 15

• Difficulty Level : Easy
• Last Updated : 14 Apr, 2021

Given a very large number. Check its divisibility by 15.
Examples:

```Input: 31
Output: No

Input : num = "156457463274623847239840239
402394085458848462385346236
482374823647643742374523747
264723762374620"
Output: Yes
Given number is divisible by 15```

A number is divisible by 15 if it is divisible by 5 (if the last digit is 5 or 0), and it is divisible by 3 (if sum of digits is divisible by 3).
Here, used accumulate function to sum up all the numbers.

## C++

 `// CPP program to check if a large``// number is divisible by 15``#include ` `using` `namespace` `std;` `// function to check if a large number``// is divisible by 15``bool` `isDivisible(string s)``{``    ``// length of string``    ``int` `n = s.length();` `    ``// check divisibility by 5``    ``if` `(s[n - 1] != ``'5'` `and s[n - 1] != ``'0'``)``        ``return` `false``;` `    ``// Sum of digits``    ``int` `sum = accumulate(begin(s), end(s), 0) - ``'0'` `* n;` `    ``// if divisible by 3``    ``return` `(sum % 3 == 0);``}` `// driver program``int` `main()``{``    ``string s = ``"15645746327462384723984023940239"``;``    ``isDivisible(s)? cout << ``"Yes\n"``: cout << ``"No\n"``;``    ``string s1 = ``"15645746327462384723984023940235"``;``    ``isDivisible(s1)? cout << ``"Yes\n"``: cout << ``"No\n"``;``    ``return` `0;``}`

## Java

 `// Java program to check if a large``// number is divisible by 15``import` `java.util.*;` `class` `GFG``{``     ` `// function to check if a large``// number is divisible by 15``public` `static` `boolean` `isDivisible(String S)``{``    ``// length of string``    ``int` `n = S.length();``    ` `    ``// check divisibility by 5``    ``if` `(S.charAt(n - ``1``) != ``'5'` `&&``        ``S.charAt(n - ``1``) != ``'0'``)``        ``return` `false``;``        ` `    ``// Sum of digits``    ``int` `sum = ``0``;``    ``for``(``int` `i = ``0``; i < S.length(); i++)``        ``sum += (``int``)S.charAt(i);``        ` `        ``// if divisible by 3``        ``if``(sum % ``3` `== ``0``)``            ``return` `true``;``        ``else``            ``return` `false``;``}``    ` `// Driver code``public` `static` `void` `main (String[] args)``{``    ``String S = ``"15645746327462384723984023940239"``;``    ``if``(isDivisible(S) == ``true``)``        ``System.out.println(``"Yes"``);``    ``else``        ``System.out.println(``"No"``);``        ` `    ``String S1 = ``"15645746327462384723984023940235"``;``    ``if``(isDivisible(S1) == ``true``)``        ``System.out.println(``"Yes"``);``    ``else``        ``System.out.println(``"No"``);``    ``}``}``        ` `// This code is contributed``// by Akanksha Rai(Abby_akku)`

## Python3

 `# Python3 program to check if``# a large number is``# divisible by 15` `# to find sum``def` `accumulate(s):``    ``acc ``=` `0``;``    ``for` `i ``in` `range``(``len``(s)):``        ``acc ``+``=` `ord``(s[i]) ``-` `48``;``    ``return` `acc;` `# function to check``# if a large number``# is divisible by 15``def` `isDivisible(s):``    ``# length of string``    ``n ``=` `len``(s);` `    ``# check divisibility by 5``    ``if` `(s[n ``-` `1``] !``=` `'5'` `and` `s[n ``-` `1``] !``=` `'0'``):``        ``return` `False``;` `    ``# Sum of digits``    ``sum` `=` `accumulate(s);``    ` `    ``# if divisible by 3``    ``return` `(``sum` `%` `3` `=``=` `0``);`  `# Driver Code``s ``=` `"15645746327462384723984023940239"``;``if` `isDivisible(s):``    ``print``(``"Yes"``);``else``:``    ``print``(``"No"``);` `s ``=` `"15645746327462384723984023940235"``;``if` `isDivisible(s):``    ``print``(``"Yes"``);``else``:``    ``print``(``"No"``);` `# This code is contributed by mits`

## C#

 `// C# program to check if a large``// number is divisible by 15``using` `System;` `class` `GFG``{``// function to check if a large``// number is divisible by 15``public` `static` `bool` `isDivisible(String S)``{``    ``// length of string``    ``int` `n = S.Length;``    ` `    ``// check divisibility by 5``    ``if` `(S[n - 1] != ``'5'` `&&``        ``S[n - 1] != ``'0'``)``        ``return` `false``;``        ` `    ``// Sum of digits``    ``int` `sum = 0;``    ``for``(``int` `i = 0; i < S.Length; i++)``        ``sum += (``int``)S[i];``        ` `        ``// if divisible by 3``        ``if``(sum % 3 == 0)``            ``return` `true``;``        ``else``            ``return` `false``;``}``    ` `// Driver code``public` `static` `void` `Main()``{``    ``String S = ``"15645746327462384723984023940239"``;``    ``if``(isDivisible(S) == ``true``)``        ``Console.WriteLine(``"Yes"``);``    ``else``        ``Console.WriteLine(``"No"``);``        ` `    ``String S1 = ``"15645746327462384723984023940235"``;``    ``if``(isDivisible(S1) == ``true``)``        ``Console.WriteLine(``"Yes"``);``    ``else``        ``Console.WriteLine(``"No"``);``    ``}``}``        ` `// This code is contributed``// by mits`

## PHP

 ``

## Javascript

 ``

Output:

```No
Yes```

Time complexity: O(number of digits)
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