# Check for integer overflow on multiplication

Given two integer a and b, find whether their product (a x b) exceed the signed 64 bit integer or not. If it exceed print Yes else print No.

Examples:

```Input : a = 100, b = 200
Output : No

Input : a = 10000000000,
b = -10000000000
Output : Yes
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach :

1. If either of the number is 0, then it will never exceed the range.
2. Else if the product of the two divided by one equals the other, then also it will be in range.
3. In any other case overflow will occur.

## C++

 `// CPP program to check for integer ` `// overflow on multiplication ` `#include ` `using` `namespace` `std; ` ` `  `// Function to check whether there is ` `// overflow in a * b or not. It returns ` `// true if there is overflow. ` `bool` `isOverflow(``long` `long` `a, ``long` `long` `b) ` `{ ` `    ``// Check if either of them is zero ` `    ``if` `(a == 0 || b == 0)  ` `        ``return` `false``; ` `     `  `    ``long` `long` `result = a * b; ` `    ``if` `(a == result / b) ` `        ``return` `false``; ` `    ``else` `        ``return` `true``; ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``long` `long` `a = 10000000000, b = -10000000000; ` `    ``if` `(isOverflow(a, b)) ` `        ``cout << ``"Yes"``; ` `    ``else` `        ``cout << ``"No"``; ` `    ``return` `0; ` `} `

## Java

 `// Java program to check for integer ` `// overflow on multiplication ` `import` `java.util.*; ` `import` `java.lang.*; ` ` `  `public` `class` `GfG{ ` `     `  `    ``// Function to check whether there is ` `    ``// overflow in a * b or not. It  ` `    ``// returns true if there is overflow. ` `    ``static` `Boolean isOverflow( ``long` `a, ``long` `b) ` `    ``{ ` `        ``// Check if either of them is zero ` `        ``if` `(a == ``0` `|| b == ``0``)  ` `            ``return` `false``; ` `     `  `        ``long` `result = a * b; ` `        ``if` `(a == result / b) ` `            ``return` `false``; ` `        ``else` `            ``return` `true``; ` `    ``} ` `     `  `    ``// driver function ` `    ``public` `static` `void` `main(String argc[]) ` `    ``{ ` `        ``long` `a = Long.parseLong(``"10000000000"``); ` `        ``long` `b = Long.parseLong(``"-10000000000"``);  ` `         `  `        ``if` `(isOverflow(a, b)) ` `        ``System.out.print(``"Yes"``); ` `    ``else` `        ``System.out.print(``"No"``); ` `    ``} ` `} ` ` `  `// This code is contributed by Prerna Saini `

## Python3

 `# Python program to check for integer  ` `# overflow on multiplication  ` ` `  `# Function to check whether there is  ` `# overflow in a * b or not. It returns  ` `# true if there is overflow.  ` `def` `isOverflow(a, b):  ` ` `  `    ``# Check if either of them is zero  ` `    ``if` `(a ``=``=` `0` `or` `b ``=``=` `0``) : ` `        ``return` `False` ` `  `    ``result ``=` `a ``*` `b ` `    ``if` `(result >``=` `9223372036854775807` `or`  `        ``result <``=` `-``9223372036854775808``): ` `        ``result``=``0` `    ``if` `(a ``=``=` `(result ``/``/` `b)): ` `        ``print``(result ``/``/` `b) ` `        ``return` `False` `    ``else``: ` `        ``return` `True` ` `  `# Driver code  ` `if` `__name__ ``=``=``"__main__"``: ` `    ``a ``=` `10000000000` `    ``b ``=` `-``10000000000` `    ``if` `(isOverflow(a, b)): ` `        ``print``( ``"Yes"``) ` `    ``else``: ` `        ``print``( ``"No"``) ` `         `  `# This code is contributed ` `# Shubham Singh(SHUBHAMSINGH10) `

## C#

 `// C# program to check for integer ` `// overflow on multiplication ` `using` `System; ` ` `  `public` `class` `GfG ` `{ ` `     `  `    ``// Function to check whether there is ` `    ``// overflow in a * b or not. It  ` `    ``// returns true if there is overflow. ` `    ``static` `bool` `isOverflow( ``long` `a, ``long` `b) ` `    ``{ ` `        ``// Check if either of them is zero ` `        ``if` `(a == 0 || b == 0)  ` `            ``return` `false``; ` `     `  `        ``long` `result = a * b; ` `        ``if` `(a == result / b) ` `            ``return` `false``; ` `        ``else` `            ``return` `true``; ` `    ``} ` `     `  `    ``// Driver function ` `    ``public` `static` `void` `Main() ` `    ``{ ` `        ``long` `a = 10000000000; ` `        ``long` `b = -10000000000 ; ` `         `  `        ``if` `(isOverflow(a, b)) ` `            ``Console.WriteLine(``"Yes"``); ` `        ``else` `            ``Console.WriteLine(``"No"``); ` `    ``} ` `} ` ` `  `// This code is contributed by vt_m `

## PHP

 ` `

Output:

```Yes
```

Time complexity : O(1)

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