# Check if two numbers have same number of digits

• Last Updated : 10 May, 2021

Given two integers A and B, the task is to check whether both the numbers have an equal number of digits.
Examples:

Input: A = 12, B = 1
Output: No
Input: A = 20, B = 99
Output: Yes

Approach: While both the numbers are > 0, keep dividing both the numbers by 10. Finally, check if both the numbers are 0. If any one of them is not 0 then they had an unequal numbers of digits.
Below is the implementation of the above approach:

## C++

 `// C++ implementation of the approach``#include ``using` `namespace` `std;` `// Function that return true if A and B``// have same number of digits``bool` `sameLength(``int` `A, ``int` `B)``{``    ``while` `(A > 0 && B > 0) {``        ``A = A / 10;``        ``B = B / 10;``    ``}` `    ``// Both must be 0 now if``    ``// they had same lengths``    ``if` `(A == 0 && B == 0)``        ``return` `true``;``    ``return` `false``;``}` `// Driver code``int` `main()``{``    ``int` `A = 21, B = 1;` `    ``if` `(sameLength(A, B))``        ``cout << ``"Yes"``;``    ``else``        ``cout << ``"No"``;` `    ``return` `0;``}`

## Java

 `// Java implementation of the approach``import` `java.io.*;` `class` `GFG``{``    ` `// Function that return true if A and B``// have same number of digits``static` `boolean` `sameLength(``int` `A, ``int` `B)``{``    ``while` `((A > ``0``) && (B > ``0``))``    ``{``        ``A = A / ``10``;``        ``B = B / ``10``;``    ``}` `    ``// Both must be 0 now if``    ``// they had same lengths``    ``if` `((A == ``0` `)&& (B == ``0``))``        ``return` `true``;``    ``return` `false``;``}` `// Driver code``public` `static` `void` `main (String[] args)``{` `    ``int` `A = ``21``, B = ``1``;``    ``if` `(sameLength(A, B))``        ``System.out.println (``"Yes"``);``    ``else``        ``System.out.println(``"No"``);` `}``}` `// This code is contributed by @tushil.`

## Python3

 `    ` `# Python implementation of the approach` `# Function that return true if A and B``# have same number of digits``def` `sameLength(A, B):``    ``while` `(A > ``0` `and` `B > ``0``):``        ``A ``=` `A ``/` `10``;``        ``B ``=` `B ``/` `10``;` `    ``# Both must be 0 now if``    ``# they had same lengths``    ``if` `(A ``=``=` `0` `and` `B ``=``=` `0``):``        ``return` `True``;``    ``return` `False``;` `# Driver code``A ``=` `21``; B ``=` `1``;` `if` `(sameLength(A, B)):``    ``print``(``"Yes"``);``else``:``    ``print``(``"No"``);` `# This code contributed by PrinciRaj1992`

## C#

 `// C# implementation of the approach``using` `System;` `class` `GFG``{``        ` `// Function that return true if A and B``// have same number of digits``static` `bool` `sameLength(``int` `A, ``int` `B)``{``    ``while` `((A > 0) && (B > 0))``    ``{``        ``A = A / 10;``        ``B = B / 10;``    ``}` `    ``// Both must be 0 now if``    ``// they had same lengths``    ``if` `((A == 0 )&& (B == 0))``        ``return` `true``;``    ``return` `false``;``}` `// Driver code``static` `public` `void` `Main ()``{``        ` `    ``int` `A = 21, B = 1;``    ``if` `(sameLength(A, B))``            ``Console.WriteLine(``"Yes"``);``    ``else``        ``Console.WriteLine(``"No"``);` `}``}` `// This code is contributed by ajit..`

## Javascript

 ``
Output:
`No`

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