# Check if two numbers have same number of digits

Given two integers A and B, the task is to check whether both the numbers have equal number of digits.

Examples:

Input: A = 12, B = 1
Output: No

Input: A = 20, B = 99
Output: Yes

Approach: While both the numbers are > 0, keep dividing both the numbers by 10. Finally, check if both the numbers are 0. If any one of them is not 0 then they had unequal number of digits.

Below is the implementation of the above approach:

## C++

 // C++ implementation of the approach #include using namespace std;    // Function that return true if A and B // have same number of digits bool sameLength(int A, int B) {     while (A > 0 && B > 0) {         A = A / 10;         B = B / 10;     }        // Both must be 0 now if     // they had same lengths     if (A == 0 && B == 0)         return true;     return false; }    // Driver code int main() {     int A = 21, B = 1;        if (sameLength(A, B))         cout << "Yes";     else         cout << "No";        return 0; }

## Java

 // Java implementation of the approach import java.io.*;    class GFG  {        // Function that return true if A and B // have same number of digits static boolean sameLength(int A, int B) {     while ((A > 0) && (B > 0))     {         A = A / 10;         B = B / 10;     }        // Both must be 0 now if     // they had same lengths     if ((A == 0 )&& (B == 0))         return true;     return false; }    // Driver code public static void main (String[] args)  {        int A = 21, B = 1;     if (sameLength(A, B))         System.out.println ("Yes");     else         System.out.println("No");    } }    // This code is contributed by @tushil.

## Python3

 # Python implementation of the approach    # Function that return true if A and B # have same number of digits def sameLength(A, B):     while (A > 0 and B > 0):         A = A / 10;         B = B / 10;        # Both must be 0 now if     # they had same lengths     if (A == 0 and B == 0):         return True;     return False;    # Driver code A = 21; B = 1;    if (sameLength(A, B)):     print("Yes"); else:     print("No");    # This code contributed by PrinciRaj1992

## C#

 // C# implementation of the approach using System;    class GFG {            // Function that return true if A and B // have same number of digits static bool sameLength(int A, int B) {     while ((A > 0) && (B > 0))     {         A = A / 10;         B = B / 10;     }        // Both must be 0 now if     // they had same lengths     if ((A == 0 )&& (B == 0))         return true;     return false; }    // Driver code static public void Main () {                int A = 21, B = 1;     if (sameLength(A, B))             Console.WriteLine("Yes");     else         Console.WriteLine("No");    } }    // This code is contributed by ajit..

Output:

No

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Improved By : jit_t, princiraj1992

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