# Check if two numbers have same number of digits

Given two integers A and B, the task is to check whether both the numbers have equal number of digits.

Examples:

Input: A = 12, B = 1
Output: No

Input: A = 20, B = 99
Output: Yes

Approach: While both the numbers are > 0, keep dividing both the numbers by 10. Finally, check if both the numbers are 0. If any one of them is not 0 then they had unequal number of digits.

Below is the implementation of the above approach:

## C++

 `// C++ implementation of the approach ` `#include ` `using` `namespace` `std; ` ` `  `// Function that return true if A and B ` `// have same number of digits ` `bool` `sameLength(``int` `A, ``int` `B) ` `{ ` `    ``while` `(A > 0 && B > 0) { ` `        ``A = A / 10; ` `        ``B = B / 10; ` `    ``} ` ` `  `    ``// Both must be 0 now if ` `    ``// they had same lengths ` `    ``if` `(A == 0 && B == 0) ` `        ``return` `true``; ` `    ``return` `false``; ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``int` `A = 21, B = 1; ` ` `  `    ``if` `(sameLength(A, B)) ` `        ``cout << ``"Yes"``; ` `    ``else` `        ``cout << ``"No"``; ` ` `  `    ``return` `0; ` `} `

## Java

 `// Java implementation of the approach ` `import` `java.io.*; ` ` `  `class` `GFG  ` `{ ` `     `  `// Function that return true if A and B ` `// have same number of digits ` `static` `boolean` `sameLength(``int` `A, ``int` `B) ` `{ ` `    ``while` `((A > ``0``) && (B > ``0``)) ` `    ``{ ` `        ``A = A / ``10``; ` `        ``B = B / ``10``; ` `    ``} ` ` `  `    ``// Both must be 0 now if ` `    ``// they had same lengths ` `    ``if` `((A == ``0` `)&& (B == ``0``)) ` `        ``return` `true``; ` `    ``return` `false``; ` `} ` ` `  `// Driver code ` `public` `static` `void` `main (String[] args)  ` `{ ` ` `  `    ``int` `A = ``21``, B = ``1``; ` `    ``if` `(sameLength(A, B)) ` `        ``System.out.println (``"Yes"``); ` `    ``else` `        ``System.out.println(``"No"``); ` ` `  `} ` `} ` ` `  `// This code is contributed by @tushil.  `

## Python3

 `     `  `# Python implementation of the approach ` ` `  `# Function that return true if A and B ` `# have same number of digits ` `def` `sameLength(A, B): ` `    ``while` `(A > ``0` `and` `B > ``0``): ` `        ``A ``=` `A ``/` `10``; ` `        ``B ``=` `B ``/` `10``; ` ` `  `    ``# Both must be 0 now if ` `    ``# they had same lengths ` `    ``if` `(A ``=``=` `0` `and` `B ``=``=` `0``): ` `        ``return` `True``; ` `    ``return` `False``; ` ` `  `# Driver code ` `A ``=` `21``; B ``=` `1``; ` ` `  `if` `(sameLength(A, B)): ` `    ``print``(``"Yes"``); ` `else``: ` `    ``print``(``"No"``); ` ` `  `# This code contributed by PrinciRaj1992 `

## C#

 `// C# implementation of the approach ` `using` `System; ` ` `  `class` `GFG ` `{ ` `         `  `// Function that return true if A and B ` `// have same number of digits ` `static` `bool` `sameLength(``int` `A, ``int` `B) ` `{ ` `    ``while` `((A > 0) && (B > 0)) ` `    ``{ ` `        ``A = A / 10; ` `        ``B = B / 10; ` `    ``} ` ` `  `    ``// Both must be 0 now if ` `    ``// they had same lengths ` `    ``if` `((A == 0 )&& (B == 0)) ` `        ``return` `true``; ` `    ``return` `false``; ` `} ` ` `  `// Driver code ` `static` `public` `void` `Main () ` `{ ` `         `  `    ``int` `A = 21, B = 1; ` `    ``if` `(sameLength(A, B)) ` `            ``Console.WriteLine(``"Yes"``); ` `    ``else` `        ``Console.WriteLine(``"No"``); ` ` `  `} ` `} ` ` `  `// This code is contributed by ajit..  `

Output:

```No
```

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Improved By : jit_t, princiraj1992

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