Given a Binary Tree with distinct nodes. Given two nodes node1 and node2, check if the two nodes lies in the same subtree of the root node. That is, either of the left and right subtrees of the root node.
For Example: In the above binary tree, node 3 and 8 are in the same subtree but 4 and 5 are in different subtree.
Prerequisite: Check if a node exist in Binary Tree.
The idea is similar of searching a node in Binary Tree. There are four different cases:
- If both node1 and node2 are in left subtree of root node.
- If both node1 and node2 are in right subtree of the root node.
- If node1 is in the left subtree of the root node and node2 is in the right subtree of root node.
- If node1 is in the right subtree of the root node and node2 is in the left subtree of root node.
Use the approach of searching a node in Binary Tree and check if any of the first two cases listed above is True. If any of the first two cases listed above is found True then print YES otherwise print NO.
Below is the implementation of the above approach:
- Number of leaf nodes in the subtree of every node of an n-ary tree
- Convert a Binary Tree such that every node stores the sum of all nodes in its right subtree
- Change a Binary Tree so that every node stores sum of all nodes in left subtree
- Sum of nodes on the longest path from root to leaf node
- Check whether the given node is in the path between the nodes U and V
- Subtree of all nodes in a tree using DFS
- Queries for M-th node in the DFS of subtree
- Find the Kth node in the DFS traversal of a given subtree in a Tree
- Check if the given Binary Tree have a Subtree with equal no of 1's and 0's
- Print nodes at k distance from root
- Print nodes at k distance from root | Iterative
- Count of nodes which are at a distance X from root and leaves
- Maximum XOR with given value in the path from root to given node in the tree
- Find root of the tree where children id sum for every node is given
- Remove nodes on root to leaf paths of length < K
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