Check if two arrays are permutations of each other using Mathematical Operation

Given two unsorted arrays of same size where arr[i] >= 0 for all i, the task is to check if two arrays are permutations of each other or not.

Examples:

Input: arr1[] = {2, 1, 3, 5, 4, 3, 2}
arr2[] = {3, 2, 2, 4, 5, 3, 1}
Output: Yes

Input: arr1[] = {2, 1, 3, 5}
arr2[] = {3, 2, 2, 4}
Output: No

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

It has been already discussed in Check if two arrays are permutations of each other using Sorting and Hashing. But in this post, a different approach is discussed.

Approach:

1. Traverse the first array A, add and multiply all the elements and store them in variables as Sum1 and Mul1 respectively.
2. Similarly, traverse the second array B, add and multiply all the elements and store them in variables as Sum2 and Mul2 respectively.
3. Now, compare both sum1, sum2 and mul1, mul2. If Sum1 == Sum2 and Mul1 == Mul2, then both arrays are permutations of each other, else not.

Below is the implementation of above approach:

C++

 // CPP code to check if arrays // are permutations of eah other #include using namespace std;    // Function to check if arrays // are permutaitons of each other. bool arePermutations(int a[], int b[], int n, int m) {        int sum1 = 0, sum2 = 0, mul1 = 1, mul2 = 1;        // Calculating sum and multiply of first array     for (int i = 0; i < n; i++) {         sum1 += a[i];         mul1 *= a[i];     }        // Calculating sum and multiply of second array     for (int i = 0; i < m; i++) {         sum2 += b[i];         mul2 *= b[i];     }        // If sum and mul of both arrays are equal,     // return true, else return false.     return ((sum1 == sum2) && (mul1 == mul2)); }    // Driver code int main() {        int a[] = { 1, 3, 2 };     int b[] = { 3, 1, 2 };        int n = sizeof(a) / sizeof(int);     int m = sizeof(b) / sizeof(int);        if (arePermutations(a, b, n, m))          cout << "Yes" << endl;            else         cout << "No" << endl;        return 0; }

Java

 // Java code to check if arrays // are permutations of eah other    import java.io.*;    class GFG {       // Function to check if arrays // are permutaitons of each other. static boolean arePermutations(int a[], int b[], int n, int m) {        int sum1 = 0, sum2 = 0, mul1 = 1, mul2 = 1;        // Calculating sum and multiply of first array     for (int i = 0; i < n; i++) {         sum1 += a[i];         mul1 *= a[i];     }        // Calculating sum and multiply of second array     for (int i = 0; i < m; i++) {         sum2 += b[i];         mul2 *= b[i];     }        // If sum and mul of both arrays are equal,     // return true, else return false.     return ((sum1 == sum2) && (mul1 == mul2)); }    // Driver code        public static void main (String[] args) {             int a[] = { 1, 3, 2 };     int b[] = { 3, 1, 2 };        int n = a.length;     int m = b.length;        if (arePermutations(a, b, n, m)==true)          System.out.println( "Yes");            else         System.out.println( "No");     } } // This code is contributed by  inder_verma..

Python3

 # Python 3 program to check if arrays  # are permutations of eah other     # Function to check if arrays  # are permutaitons of each other def arePermutations(a, b, n, m) :        sum1, sum2, mul1, mul2 = 0, 0, 1, 1        # Calculating sum and multiply of first array      for i in range(n) :         sum1 += a[i]         mul1 *= a[i]        # Calculating sum and multiply of second array      for i in range(m) :         sum2 += b[i]         mul2 *= b[i]        # If sum and mul of both arrays are equal,      # return true, else return false.     return((sum1 == sum2) and (mul1 == mul2))       # Driver code      if __name__ == "__main__" :        a = [ 1, 3, 2]     b = [ 3, 1, 2]        n = len(a)     m = len(b)        if arePermutations(a, b, n, m) :         print("Yes")        else :         print("No")        # This code is contributed by ANKITRAI1

C#

 // C# code to check if arrays // are permutations of eah other using System;    class GFG  {    // Function to check if arrays // are permutaitons of each other. static bool arePermutations(int[] a, int[] b,                              int n, int m) {        int sum1 = 0, sum2 = 0,         mul1 = 1, mul2 = 1;        // Calculating sum and multiply      // of first array     for (int i = 0; i < n; i++)     {         sum1 += a[i];         mul1 *= a[i];     }        // Calculating sum and multiply     // of second array     for (int i = 0; i < m; i++)     {         sum2 += b[i];         mul2 *= b[i];     }        // If sum and mul of both arrays      // are equal, return true, else      // return false.     return ((sum1 == sum2) &&             (mul1 == mul2)); }    // Driver code public static void Main () {     int[] a = { 1, 3, 2 };     int[] b = { 3, 1, 2 };            int n = a.Length;     int m = b.Length;            if (arePermutations(a, b, n, m) == true)          Console.Write( "Yes");            else         Console.Write( "No"); } }    // This code is contributed  // by ChitraNayal

PHP



Output:

Yes

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