# Check if the Xor of the frequency of all digits of a number N is zero or not

• Last Updated : 28 Apr, 2021

Given a number N, the task is to check if xor value of the frequency of the digits is zero or not.
Examples:

```Input: N = 122233
Output: Yes
Frequencies of 1, 2 and 3 are 1, 3, 2 respectively.
And Xor of 1, 3 and 2 is 0.

Input: N = 123
Output: No```

Approach: Count the frequency of all the digits and then iterate over all frequency and xor them if the answer is zero then print Yes else No.
Below is the implementation of the above approach:

## C++

 `// C++ implementation of the above approach``#include``using` `namespace` `std;` `bool` `check(``int` `s)``{` `// creating a frequency array``    ``int` `freq[10] = {0},r;``    ``while``(s != 0)``    ``{` `    ``// Finding the last digit of the number``        ``r = s % 10;` `        ``// Dividing the number by 10 to``        ``// eliminate last digit``        ``s = ``int``(s / 10);` `        ``// counting frequency of each digit``        ``freq[r] += 1;``    ``}` `        `  `    ``int` `xor__ = 0;` `    ``// checking if the xor of all frequency is zero or not``    ``for` `(``int` `i=0;i<10;i++)``    ``{``    ``xor__ = xor__ ^ freq[i];``    ``if``(xor__ == 0)``        ``return` `true``;``    ``else``        ``return` `false``;``    ``}``        ` `}` `// Driver function``int` `main()``{` `int` `s = 122233;``if``(check(s))``cout<<``"Yes"``<

## Java

 `// Java implementation of the above approach``class` `GFG``{``static` `boolean` `check(``int` `s)``{` `// creating a frequency array``    ``int``[] freq = ``new` `int``[``10``];``    ` `    ``int` `r,i;``    ``for``(i=``0``;i<``10``;i++)``    ``{``        ``freq[i]= ``0``;``    ``}``    ``while``(s != ``0``)``    ``{` `    ``// Finding the last digit of the number``        ``r = s % ``10``;` `        ``// Dividing the number by 10 to``        ``// eliminate last digit``        ``s = (``int``)(s / ``10``);` `        ``// counting frequency of each digit``        ``freq[r] += ``1``;``    ``}` `        `  `    ``int` `xor__ = ``0``;` `    ``// checking if the xor of all frequency is zero or not``    ``for` `( i=``0``;i<``10``;i++)``    ``{``    ``xor__ = xor__ ^ freq[i];``    ``if``(xor__ == ``0``)``        ``return` `true``;``    ``else``        ``return` `false``;``    ``}``    ``return` `true``;``        ` `}` `// Driver function``    ``public` `static` `void` `main(String[] args) {``        ``int` `s = ``122233``;``        ``if``(check(s))``            ``System.out.println(``"Yes\n"``);``        ``else``            ``System.out.println(``"No\n"``);``}` `// This code is contributed by``// Rajput-Ji``}`

## Python3

 `# Python implementation of the above approach``def` `check(s):` `    ``# creating a frequency array``    ``freq ``=``[``0``]``*``10``    ``while``(s !``=` `0``):` `        ``# Finding the last digit of the number``        ``r ``=` `s ``%` `10` `        ``# Dividing the number by 10 to``        ``# eliminate last digit``        ``s ``=` `s``/``/``10` `        ``# counting frequency of each digit``        ``freq[r]``+``=` `1` `    ``xor ``=` `0` `    ``# checking if the xor of all frequency is zero or not``    ``for` `i ``in` `range``(``10``):``        ``xor ``=` `xor ^ freq[i]``    ``if``(xor ``=``=` `0``):``        ``return` `True``    ``else``:``        ``return` `False` `s ``=` `122233``if``(check(s)):``    ``print``(``"Yes"``)``else``:``    ``print``(``"No"``)`

## C#

 `// C# implementation of the above approach``using` `System;` `class` `GFG``{``    ` `static` `bool` `check(``int` `s)``{` `    ``// creating a frequency array``    ``int``[] freq = ``new` `int``[10];``    ` `    ``int` `r, i;``    ``for``(i = 0; i < 10; i++)``    ``{``        ``freq[i]= 0;``    ``}``    ``while``(s != 0)``    ``{` `    ``// Finding the last digit of the number``        ``r = s % 10;` `        ``// Dividing the number by 10 to``        ``// eliminate last digit``        ``s = (``int``)(s / 10);` `        ``// counting frequency of each digit``        ``freq[r] += 1;``    ``}` `    ``int` `xor__ = 0;` `    ``// checking if the xor of all frequency is zero or not``    ``for` `( i = 0; i < 10; i++)``    ``{``    ``xor__ = xor__ ^ freq[i];``    ``if``(xor__ == 0)``        ``return` `true``;``    ``else``        ``return` `false``;``    ``}``    ``return` `true``;``        ` `}` `    ``// Driver code``    ``public` `static` `void` `Main()``    ``{``        ``int` `s = 122233;``        ``if``(check(s))``            ``Console.Write(``"Yes\n"``);``        ``else``            ``Console.Write(``"No\n"``);``    ``}``}` `// This code is contributed by Ita_c.`

## PHP

 ``

## Javascript

 ``

Output:

`Yes`

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