# Check if the Xor of the frequency of all digits of a number N is zero or not

Given a number N, the task is to check if xor value of the frequency of the digits is zero or not.

Examples:

```Input: N = 122233
Output: Yes
Frequencies of 1, 2 and 3 are 1, 3, 2 respectively.
And Xor of 1, 3 and 2 is 0.

Input: N = 123
Output: No
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: Count the frequency of all the digits and then iterate over all frequency and xor them if the answer is zero then print Yes else No.

Below is the implementation of the above approach:

## C++

 `// C++ implementation of the above approach ` `#include ` `using` `namespace` `std; ` ` `  `bool` `check(``int` `s) ` `{ ` ` `  `// creating a frequency array ` `    ``int` `freq[10] = {0},r; ` `    ``while``(s != 0) ` `    ``{ ` ` `  `    ``// Finding the last digit of the number ` `        ``r = s % 10; ` ` `  `        ``// Dividing the number by 10 to  ` `        ``// eliminate last digit ` `        ``s = ``int``(s / 10); ` ` `  `        ``// counting frequency of each digit  ` `        ``freq[r] += 1; ` `    ``} ` ` `  `         `  ` `  `    ``int` `xor__ = 0; ` ` `  `    ``// checking if the xor of all frequency is zero or not ` `    ``for` `(``int` `i=0;i<10;i++) ` `    ``{ ` `    ``xor__ = xor__ ^ freq[i]; ` `    ``if``(xor__ == 0) ` `        ``return` `true``; ` `    ``else` `        ``return` `false``; ` `    ``}  ` `         `  `} ` ` `  `// Driver function ` `int` `main() ` `{ ` ` `  `int` `s = 122233; ` `if``(check(s)) ` `cout<<``"Yes"``<

## Java

 `// Java implementation of the above approach ` `class` `GFG ` `{ ` `static` `boolean` `check(``int` `s) ` `{ ` ` `  `// creating a frequency array ` `    ``int``[] freq = ``new` `int``[``10``]; ` `     `  `    ``int` `r,i; ` `    ``for``(i=``0``;i<``10``;i++) ` `    ``{ ` `        ``freq[i]= ``0``; ` `    ``} ` `    ``while``(s != ``0``) ` `    ``{ ` ` `  `    ``// Finding the last digit of the number ` `        ``r = s % ``10``; ` ` `  `        ``// Dividing the number by 10 to  ` `        ``// eliminate last digit ` `        ``s = (``int``)(s / ``10``); ` ` `  `        ``// counting frequency of each digit  ` `        ``freq[r] += ``1``; ` `    ``} ` ` `  `         `  ` `  `    ``int` `xor__ = ``0``; ` ` `  `    ``// checking if the xor of all frequency is zero or not ` `    ``for` `( i=``0``;i<``10``;i++) ` `    ``{ ` `    ``xor__ = xor__ ^ freq[i]; ` `    ``if``(xor__ == ``0``) ` `        ``return` `true``; ` `    ``else` `        ``return` `false``; ` `    ``} ` `    ``return` `true``; ` `         `  `} ` ` `  `// Driver function ` `    ``public` `static` `void` `main(String[] args) { ` `        ``int` `s = ``122233``; ` `        ``if``(check(s)) ` `            ``System.out.println(``"Yes\n"``); ` `        ``else` `            ``System.out.println(``"No\n"``); ` `} ` ` `  `// This code is contributed by ` `// Rajput-Ji ` `} `

## Python3

 `# Python implementation of the above approach ` `def` `check(s): ` ` `  `    ``# creating a frequency array ` `    ``freq ``=``[``0``]``*``10` `    ``while``(s !``=` `0``): ` ` `  `        ``# Finding the last digit of the number ` `        ``r ``=` `s ``%` `10` ` `  `        ``# Dividing the number by 10 to  ` `        ``# eliminate last digit ` `        ``s ``=` `s``/``/``10` ` `  `        ``# counting frequency of each digit  ` `        ``freq[r]``+``=` `1` ` `  `    ``xor ``=` `0` ` `  `    ``# checking if the xor of all frequency is zero or not ` `    ``for` `i ``in` `range``(``10``): ` `        ``xor ``=` `xor ^ freq[i] ` `    ``if``(xor ``=``=` `0``): ` `        ``return` `True` `    ``else``: ` `        ``return` `False` ` `  `s ``=` `122233` `if``(check(s)): ` `    ``print``(``"Yes"``) ` `else``: ` `    ``print``(``"No"``) `

## C#

 `// C# implementation of the above approach ` `using` `System; ` ` `  `class` `GFG ` `{ ` `     `  `static` `bool` `check(``int` `s) ` `{ ` ` `  `    ``// creating a frequency array ` `    ``int``[] freq = ``new` `int``[10]; ` `     `  `    ``int` `r, i; ` `    ``for``(i = 0; i < 10; i++) ` `    ``{ ` `        ``freq[i]= 0; ` `    ``} ` `    ``while``(s != 0) ` `    ``{ ` ` `  `    ``// Finding the last digit of the number ` `        ``r = s % 10; ` ` `  `        ``// Dividing the number by 10 to  ` `        ``// eliminate last digit ` `        ``s = (``int``)(s / 10); ` ` `  `        ``// counting frequency of each digit  ` `        ``freq[r] += 1; ` `    ``} ` ` `  `    ``int` `xor__ = 0; ` ` `  `    ``// checking if the xor of all frequency is zero or not ` `    ``for` `( i = 0; i < 10; i++) ` `    ``{ ` `    ``xor__ = xor__ ^ freq[i]; ` `    ``if``(xor__ == 0) ` `        ``return` `true``; ` `    ``else` `        ``return` `false``; ` `    ``} ` `    ``return` `true``; ` `         `  `} ` ` `  `    ``// Driver code ` `    ``public` `static` `void` `Main() ` `    ``{ ` `        ``int` `s = 122233; ` `        ``if``(check(s)) ` `            ``Console.Write(``"Yes\n"``); ` `        ``else` `            ``Console.Write(``"No\n"``); ` `    ``} ` `} ` ` `  `// This code is contributed by Ita_c. `

## PHP

 ` `

Output:

```Yes
```

My Personal Notes arrow_drop_up

Check out this Author's contributed articles.

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.

Article Tags :
Practice Tags :

Be the First to upvote.

Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.