Check if the sum of digits of a number N divides it

Given a number N. The task is to check if the sum of digits of the given number divides the number or not. If it divides it then print YES otherwise print NO.

Examples:

Input : N = 12
Output : YES
Sum of digits = 1+2 =3 and 3 divides 12.
So, print YES.

Input : N = 15
Output : NO

Extract digits of the number and calculate the sum of all of its digits and check if the sum of digits dives N or not.

Below is the implementation of the above approach:

C++

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// C++ program to check if sum of
// digits of a number divides it
  
#include <iostream>
using namespace std;
  
// Function to check if sum of
// digits of a number divides it
int isSumDivides(int N)
{
    int temp = N;
  
    int sum = 0;
  
    // Calculate sum of all of digits of N
    while (temp) {
        sum += temp % 10;
        temp /= 10;
    }
  
    if (N % sum == 0)
        return 1;
    else
        return 0;
}
  
// Driver Code
int main()
{
    int N = 12;
  
    if (isSumDivides(N))
        cout << "YES";
    else
        cout << "NO";
  
    return 0;
}

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Java














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// Java program to check if sum of 


// digits of a number divides it 


  


import java.util.*; 


import java.lang.*; 


  


class GFG 


{ 


// Function to check if sum of 


// digits of a number divides it 


static int isSumDivides(int N) 


{ 


    int temp = N; 


  


    int sum = 0; 


  


    // Calculate sum of all of digits of N 


    while (temp > 0) 


    { 


        sum += temp % 10; 


        temp /= 10; 


    } 


  


    if (N % sum == 0) 


        return 1; 


    else


        return 0; 


} 


  


// Driver Code 


public static void main(String args[]) 


{ 


    int N = 12; 


  


    if (isSumDivides(N) == 1) 


        System.out.print("YES"); 


    else


        System.out.print("NO"); 


} 


} 


  


// This code is contributed  


// by Akanksha Rai(Abby_akku) 



















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Python3














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# Python3 program to check if sum of 


# digits of a number divides it 


  


# Function to check if sum of 


# digits of a number divides it 


def isSumDivides(N): 


  


    temp = N 


  


    sum = 0


  


    # Calculate sum of all of  


    # digits of N 


    while (temp):  


        sum += temp % 10


        temp = int(temp / 10) 


  


    if (N % sum == 0): 


        return 1


    else: 


        return 0


  


# Driver Code 


if __name__=='__main__': 


    N = 12


  


    if (isSumDivides(N)): 


        print("YES") 


    else: 


        print("NO") 


      


# This code is contributed by  


# mits 



















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C#














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// C# program to check if sum of  


// digits of a number divides it  


using System; 


  


// Function to check if sum of  


// digits of a number divides it  


class GFG 


{ 


public int isSumDivides(int N)  


{  


    int temp = N, sum = 0;  


  


    // Calculate sum of all of  


    // digits of N  


    while (temp > 0)  


    {  


        sum += temp % 10;  


        temp /= 10;  


    }  


  


    if (N % sum == 0)  


        return 1;  


    else


        return 0;  


}  


  


// Driver Code  


public static void Main()  


{  


    GFG g = new GFG(); 


    int N = 12;  


  


    if (g.isSumDivides(N) > 0)  


        Console.WriteLine("YES");  


    else


        Console.WriteLine("NO");  


}  


} 


  


// This code is contributed by Soumik 



















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PHP














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<?php 


// PHP program to check if sum of 


// digits of a number divides it 


  


// Function to check if sum of 


// digits of a number divides it 


function isSumDivides($N) 


{ 


    $temp = $N; 


  


    $sum = 0; 


  


    // Calculate sum of all of  


    // digits of N 


    while ($temp)  


    { 


        $sum += $temp % 10; 


        $temp = (int)$temp / 10; 


    } 


  


    if ($N % $sum == 0) 


        return 1; 


    else


        return 0; 


} 


  


// Driver Code 


$N = 12; 


  


if (isSumDivides($N)) 


    echo "YES"; 


else


    echo "NO"; 


      


// This code is contributed by ajit 


?> 



















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Output:


YES







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