Check if the sum of digits of a number N divides it

Given a number N. The task is to check if the sum of digits of the given number divides the number or not. If it divides it then print YES otherwise print NO.
Examples: 

Input : N = 12
Output : YES
Sum of digits = 1+2 =3 and 3 divides 12.
So, print YES.

Input : N = 15
Output : NO

Extract digits of the number and calculate the sum of all of its digits and check if the sum of digits dives N or not.
Below is the implementation of the above approach: 

C++

// C++ program to check if sum of
// digits of a number divides it

#include <iostream>
using namespace std;

// Function to check if sum of
// digits of a number divides it
int isSumDivides(int N)
{
    int temp = N;

    int sum = 0;

    // Calculate sum of all of digits of N
    while (temp) {
        sum += temp % 10;
        temp /= 10;
    }

    if (N % sum == 0)
        return 1;
    else
        return 0;
}

// Driver Code
int main()
{
    int N = 12;

    if (isSumDivides(N))
        cout << "YES";
    else
        cout << "NO";

    return 0;
}

Java

// Java program to check if sum of
// digits of a number divides it

import java.util.*;
import java.lang.*;

class GFG
{
// Function to check if sum of
// digits of a number divides it
static int isSumDivides(int N)
{
    int temp = N;

    int sum = 0;

    // Calculate sum of all of digits of N
    while (temp > 0)
    {
        sum += temp % 10;
        temp /= 10;
    }

    if (N % sum == 0)
        return 1;
    else
        return 0;
}

// Driver Code
public static void main(String args[])
{
    int N = 12;

    if (isSumDivides(N) == 1)
        System.out.print("YES");
    else
        System.out.print("NO");
}
}

// This code is contributed
// by Akanksha Rai(Abby_akku)

Python3

# Python3 program to check if sum of
# digits of a number divides it

# Function to check if sum of
# digits of a number divides it
def isSumDivides(N):

    temp = N

    sum = 0

    # Calculate sum of all of
    # digits of N
    while (temp):
        sum += temp % 10
        temp = int(temp / 10)

    if (N % sum == 0):
        return 1
    else:
        return 0

# Driver Code
if __name__=='__main__':
    N = 12

    if (isSumDivides(N)):
        print("YES")
    else:
        print("NO")

# This code is contributed by
# mits

C#

// C# program to check if sum of
// digits of a number divides it
using System;

// Function to check if sum of
// digits of a number divides it
class GFG
{
public int isSumDivides(int N)
{
    int temp = N, sum = 0;

    // Calculate sum of all of
    // digits of N
    while (temp > 0)
    {
        sum += temp % 10;
        temp /= 10;
    }

    if (N % sum == 0)
        return 1;
    else
        return 0;
}

// Driver Code
public static void Main()
{
    GFG g = new GFG();
    int N = 12;

    if (g.isSumDivides(N) > 0)
        Console.WriteLine("YES");
    else
        Console.WriteLine("NO");
}
}

// This code is contributed by Soumik

PHP

<?php
// PHP program to check if sum of
// digits of a number divides it

// Function to check if sum of
// digits of a number divides it
function isSumDivides($N)
{
    $temp = $N;

    $sum = 0;

    // Calculate sum of all of
    // digits of N
    while ($temp)
    {
        $sum += $temp % 10;
        $temp = (int)$temp / 10;
    }

    if ($N % $sum == 0)
        return 1;
    else
        return 0;
}

// Driver Code
$N = 12;

if (isSumDivides($N))
    echo "YES";
else
    echo "NO";

// This code is contributed by ajit
?>

Javascript

<script>
// javascript program to check if sum of
// digits of a number divides it
// Function to check if sum of
    // digits of a number divides it
    function isSumDivides(N) {
        var temp = N;

        var sum = 0;

        // Calculate sum of all of digits of N
        while (temp > 0) {
            sum += temp % 10;
            temp = parseInt(temp/10);
        }

        if (N % sum == 0)
            return 1;
        else
            return 0;
    }

    // Driver Code

        var N = 12;

        if (isSumDivides(N) == 1)
            document.write("YES");
        else
            document.write("NO");

// This code contributed by aashish1995
</script>

Output:

YES

Time Complexity : O(logn) 

Auxiliary Space: O(1)