# Check if the sum of digits of a number N divides it

• Last Updated : 13 Jun, 2022

Given a number N. The task is to check if the sum of digits of the given number divides the number or not. If it divides it then print YES otherwise print NO.
Examples

```Input : N = 12
Output : YES
Sum of digits = 1+2 =3 and 3 divides 12.
So, print YES.

Input : N = 15
Output : NO```

Extract digits of the number and calculate the sum of all of its digits and check if the sum of digits dives N or not.
Below is the implementation of the above approach:

## C++

 `// C++ program to check if sum of``// digits of a number divides it` `#include ``using` `namespace` `std;` `// Function to check if sum of``// digits of a number divides it``int` `isSumDivides(``int` `N)``{``    ``int` `temp = N;` `    ``int` `sum = 0;` `    ``// Calculate sum of all of digits of N``    ``while` `(temp) {``        ``sum += temp % 10;``        ``temp /= 10;``    ``}` `    ``if` `(N % sum == 0)``        ``return` `1;``    ``else``        ``return` `0;``}` `// Driver Code``int` `main()``{``    ``int` `N = 12;` `    ``if` `(isSumDivides(N))``        ``cout << ``"YES"``;``    ``else``        ``cout << ``"NO"``;` `    ``return` `0;``}`

## Java

 `// Java program to check if sum of``// digits of a number divides it` `import` `java.util.*;``import` `java.lang.*;` `class` `GFG``{``// Function to check if sum of``// digits of a number divides it``static` `int` `isSumDivides(``int` `N)``{``    ``int` `temp = N;` `    ``int` `sum = ``0``;` `    ``// Calculate sum of all of digits of N``    ``while` `(temp > ``0``)``    ``{``        ``sum += temp % ``10``;``        ``temp /= ``10``;``    ``}` `    ``if` `(N % sum == ``0``)``        ``return` `1``;``    ``else``        ``return` `0``;``}` `// Driver Code``public` `static` `void` `main(String args[])``{``    ``int` `N = ``12``;` `    ``if` `(isSumDivides(N) == ``1``)``        ``System.out.print(``"YES"``);``    ``else``        ``System.out.print(``"NO"``);``}``}` `// This code is contributed``// by Akanksha Rai(Abby_akku)`

## Python3

 `# Python3 program to check if sum of``# digits of a number divides it` `# Function to check if sum of``# digits of a number divides it``def` `isSumDivides(N):` `    ``temp ``=` `N` `    ``sum` `=` `0` `    ``# Calculate sum of all of``    ``# digits of N``    ``while` `(temp):``        ``sum` `+``=` `temp ``%` `10``        ``temp ``=` `int``(temp ``/` `10``)` `    ``if` `(N ``%` `sum` `=``=` `0``):``        ``return` `1``    ``else``:``        ``return` `0` `# Driver Code``if` `__name__``=``=``'__main__'``:``    ``N ``=` `12` `    ``if` `(isSumDivides(N)):``        ``print``(``"YES"``)``    ``else``:``        ``print``(``"NO"``)``    ` `# This code is contributed by``# mits`

## C#

 `// C# program to check if sum of``// digits of a number divides it``using` `System;` `// Function to check if sum of``// digits of a number divides it``class` `GFG``{``public` `int` `isSumDivides(``int` `N)``{``    ``int` `temp = N, sum = 0;` `    ``// Calculate sum of all of``    ``// digits of N``    ``while` `(temp > 0)``    ``{``        ``sum += temp % 10;``        ``temp /= 10;``    ``}` `    ``if` `(N % sum == 0)``        ``return` `1;``    ``else``        ``return` `0;``}` `// Driver Code``public` `static` `void` `Main()``{``    ``GFG g = ``new` `GFG();``    ``int` `N = 12;` `    ``if` `(g.isSumDivides(N) > 0)``        ``Console.WriteLine(``"YES"``);``    ``else``        ``Console.WriteLine(``"NO"``);``}``}` `// This code is contributed by Soumik`

## PHP

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## Javascript

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Output:

`YES`

Time Complexity : O(logn)

Auxiliary Space: O(1)

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