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Check if the rows of a binary matrix can be made unique by removing a single column

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  • Last Updated : 12 May, 2022

Given a binary matrix mat[][] of size M * N. The task is to check whether the row of the matrix will be unique after deleting a column from the matrix.

Example: 

Input: mat[][] = { 
{1 0 1}, 
{0 0 0}, 
{1 0 0} 

Output: Yes 
After deleting 2nd column each row of matrix become unique.

Input:mat[][] = { 
{1 0}, 
{1 0} 

Output: No 
 

Approach:  

  • Take matrix as an array of string and each row consider as single string.
  • Initialise a variable count = 0 to count duplicate rows in matrix.
  • Now take two nested loop outer loop from i = 0 to str.length() and inner loop from j = 0 to i and for each index check if str[i] == str[j] then increment count by 1 and break the loop.
  • Now check if count>= 1 then print No else print Yes.

Below is implementation of Above Approach:  

C++




// C++ program to check whether the
// Rows of Binary Matrix become unique
// After Deleting a column.
#include <bits/stdc++.h>
using namespace std;
 
// Function to check whether rows of
// Binary matrix become unique after
// Deleting a column of from matrix.
int uniqueRows(string s[], int m, int n)
{
    // Initialize variable count that
    // stores the count of duplicate rows.
    int i, j, count = 0;
 
    // Take two nested loop and
    // check whether rows already
    // get seen then increment
    // count by 1 then break the loop.
    for (i = 0; i < n; i++) {
        for (j = 0; j < i; j++) {
            if (s[i] == s[j]) {
                count++;
                break;
            }
        }
    }
 
    // Check if count>=1 then print No
    // Else print Yes.
    if (count >= 1) {
        cout << "No" << endl;
    }
    else {
        cout << "Yes" << endl;
    }
    return 0;
}
 
// Driver code.
int main()
{
    int m = 3, n = 3;
    string s[] = {
        { 1, 0, 1 },
        { 0, 0, 0 },
        { 1, 0, 0 }
    };
 
    // Function calling
    uniqueRows(s, m, n);
    return 0;
}

Java




// Java program to check whether the
// Rows of Binary Matrix become unique
// After Deleting a column.
class GFG
{
     
// Function to check whether rows of
// Binary matrix become unique after
// Deleting a column of from matrix.
static int uniqueRows(int [][]s,
                      int m, int n)
{
    // Initialize variable count that
    // stores the count of duplicate rows.
    int i, j, count = 0;
 
    // Take two nested loop and
    // check whether rows already
    // get seen then increment
    // count by 1 then break the loop.
    for (i = 0; i < n; i++)
    {
        for (j = 0; j < i; j++)
        {
            if (s[i] == s[j])
            {
                count++;
                break;
            }
        }
    }
 
    // Check if count>=1 then print No
    // Else print Yes.
    if (count >= 1)
        System.out.println("No");
    else
        System.out.println("Yes");
    return 0;
}
 
// Driver code.
public static void main(String[] args)
{
    int m = 3, n = 3;
    int s[][] = { { 1, 0, 1 },
                  { 0, 0, 0 },
                  { 1, 0, 0 } };
 
    // Function calling
    uniqueRows(s, m, n);
}
}
 
// This code is contributed by PrinciRaj1992

Python3




# Python3 program to check whether the
# Rows of Binary Matrix become unique
# After Deleting a column.
 
# Function to check whether rows of
# Binary matrix become unique after
# Deleting a column of from matrix.
def uniqueRows(s, m, n):
     
    # Initialize variable count that
    # stores the count of duplicate rows.
    i, j, count = 0, 0, 0
 
    # Take two nested loop and
    # check whether rows already
    # get seen then increment
    # count by 1 then break the loop.
    for i in range(n):
        for j in range(i):
            if (s[i] == s[j]):
                count += 1
                break
 
    # Check if count>=1 then print No
    # Else print Yes.
    if (count >= 1):
        print("No" )
    else:
        print("Yes")
 
# Driver code.
m = 3
n = 3
s = [[ 1, 0, 1 ],
     [ 0, 0, 0 ],
     [ 1, 0, 0 ]]
 
uniqueRows(s, m, n)
 
# This code is contributed by Mohit Kumar

C#




// C# program to check whether the
// Rows of Binary Matrix become unique
// After Deleting a column.
using System;
     
class GFG
{
     
// Function to check whether rows of
// Binary matrix become unique after
// Deleting a column of from matrix.
static int uniqueRows(string []s,
                      int m, int n)
{
    // Initialize variable count that
    // stores the count of duplicate rows.
    int i, j, count = 0;
 
    // Take two nested loop and
    // check whether rows already
    // get seen then increment
    // count by 1 then break the loop.
    for (i = 0; i < n; i++)
    {
        for (j = 0; j < i; j++)
        {
            if (s[i] == s[j])
            {
                count++;
                break;
            }
        }
    }
 
    // Check if count>=1 then print No
    // Else print Yes.
    if (count >= 1)
        Console.WriteLine("No");
    else
        Console.WriteLine("Yes");
    return 0;
}
 
// Driver code.
public static void Main(String[] args)
{
    int m = 3, n = 3;
    string []s = { "101","000", "100"};
 
    // Function calling
    uniqueRows(s, m, n);
}
}
     
// This code is contributed by Princi Singh

Javascript




<script>
 
// Javascript program to check whether the
// Rows of Binary Matrix become unique
// After Deleting a column.
 
// Function to check whether rows of
// Binary matrix become unique after
// Deleting a column of from matrix.
function uniqueRows(s, m, n)
{
     
    // Initialize variable count that
    // stores the count of duplicate rows.
    var i, j, count = 0;
 
    // Take two nested loop and
    // check whether rows already
    // get seen then increment
    // count by 1 then break the loop.
    for(i = 0; i < n; i++)
    {
        for(j = 0; j < i; j++)
        {
            if (s[i] == s[j])
            {
                count++;
                break;
            }
        }
    }
 
    // Check if count>=1 then print No
    // Else print Yes.
    if (count >= 1)
    {
        document.write("No");
    }
    else
    {
        document.write("Yes");
    }
}
 
// Driver code.
var m = 3, n = 3;
var s = [ [ 1, 0, 1 ],
          [ 0, 0, 0 ],
          [ 1, 0, 0 ] ];
           
// Function calling
uniqueRows(s, m, n);
 
// This code is contributed by importantly
 
</script>
Output: 
Yes

 


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