Check if number can be displayed using seven segment led

• Difficulty Level : Medium
• Last Updated : 10 May, 2021

Given a string str representing an integer and an integer led which is the count of LEDs available. The task is to check if it is possible to display the number using the given LEDs.
Note that a digit will be displayed as it is displayed on a 7 segment LED. If its possible to display the number then print Yes, otherwise print No.
Here’s an example of seven segment display: Examples:

Input: str = “999”, led = 5
Output: NO
9 takes 6 LEDs to be displayed. So 999 will require 18 LEDs
Since only 5 LEDs are available, it is not possible to display 999
Input: str = “123456789”, led = 43
Output: YES
Input: str = “123456789”, led = 20
Output: NO

Approach: Pre-compute the number of segments used by digits from 0 to 9 and store it. Now for each element of the string count the number of segments used by it. Now, if count ≤ led then print YES else print NO.

The number of segment used by digit:
0 -> 6
1 -> 2
2 -> 5
3 -> 5
4 -> 4
5 -> 5
6 -> 6
7 -> 3
8 -> 7
9 -> 6

Below is the implementation of the above approach:

C++

 // C++ implementation of above approach#include using namespace std; // Pre-computed values of segment used by digit 0 to 9.const int seg = { 6, 2, 5, 5, 4, 5, 6, 3, 7, 6 }; // Check if it is possible to display the numberstring LedRequired(string s, int led){    int count = 0;     // Finding sum of the segments used by    // each digit of the number    for (int i = 0; i < s.length(); ++i) {        count += seg[int(s[i]) - 48];    }     if (count <= led)        return "YES";    else        return "NO";} // Driven Programint main(){    string S = "123456789";    int led = 20;     // Function call to print required answer    cout << LedRequired(S, led) << endl;    return 0;}

Java

 // Java implementation of the above approachpublic class GfG{     // Check if it is possible to display the number    public static String LedRequired(String s, int led)    {        // Pre-computed values of segment used by digit 0 to 9.        int seg[] = { 6, 2, 5, 5, 4, 5, 6, 3, 7, 6 };         int count = 0;        // Finding sum of the segments used by        // each digit of the number        for (int i = 0; i < s.length(); ++i) {            count += seg[(int)(s.charAt(i)) - 48];        }               if (count <= led)            return "YES";        else            return "NO";    }     public static void main(String []args){                 String S = "123456789";        int led = 20;               // Function call to print required answer        System.out.println(LedRequired(S, led));    }} // This code is contributed by Rituraj Jain

Python3

 # Python3 implementation of above approach # Pre-computed values of segment# used by digit 0 to 9.seg = [ 6, 2, 5, 5, 4,        5, 6, 3, 7, 6 ] # Check if it is possible to# display the numberdef LedRequired(s, led) :     count = 0     # Finding sum of the segments used    # by each digit of the number    for i in range(len(s)) :        count += seg[ord(s[i]) - 48]         if (count <= led) :        return "YES"    else :        return "NO" # Driver Codeif __name__ == "__main__" :     S = "123456789"    led = 20     # Function call to print    # required answer    print(LedRequired(S, led)) # This code is contributed by Ryuga

C#

 // C# implementation of the above approachusing System;class GFG{ // Check if it is possible to display the numberpublic static String LedRequired(string s, int led){    // Pre-computed values of segment    // used by digit 0 to 9.    int[] seg = { 6, 2, 5, 5, 4, 5, 6, 3, 7, 6 };     int count = 0;         // Finding sum of the segments used by    // each digit of the number    for (int i = 0; i < s.Length; ++i)    {        count += seg[(int)(s[i]) - 48];    }     if (count <= led)        return "YES";    else        return "NO";} // Driver Codepublic static void Main(){         string S = "123456789";    int led = 20;     // Function call to print required answer    Console.WriteLine(LedRequired(S, led));}} // This code is contributed by Akanksha Rai



Javascript


Output:
NO

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