Given an angle where, . The task is to check whether it is possible to make a regular polygon with all of its interior angle equal to . If possible then print “YES”, otherwise print “NO” (without quotes).**Examples:**

Input:angle = 90Output:YES Polygons with sides 4 is possible with angle 90 degrees.Input:angle = 30Output:NO

**Approach:** The Interior angle is defined as the angle between any two adjacent sides of a regular polygon.

It is given by where, **n** is the number of sides in the polygon.

This can be written as .

On rearranging terms we get, .

Thus, if **n** is an **Integer** the answer is “YES” otherwise, answer is “NO”.

Below is the implementation of the above approach:

## C++

`// C++ implementation of above approach` `#include <bits/stdc++.h>` `using` `namespace` `std;` ` ` `// Function to check whether it is possible` `// to make a regular polygon with a given angle.` `void` `makePolygon(` `float` `a)` `{` ` ` `// N denotes the number of sides` ` ` `// of polygons possible` ` ` `float` `n = 360 / (180 - a);` ` ` `if` `(n == (` `int` `)n)` ` ` `cout << ` `"YES"` `;` ` ` `else` ` ` `cout << ` `"NO"` `;` `}` ` ` `// Driver code` `int` `main()` `{` ` ` `float` `a = 90;` ` ` ` ` `// function to print the required answer` ` ` `makePolygon(a);` ` ` ` ` `return` `0;` `}` |

## Java

`class` `GFG ` `{` `// Function to check whether ` `// it is possible to make a` `// regular polygon with a given angle. ` `static` `void` `makePolygon(` `double` `a) ` `{ ` ` ` `// N denotes the number of ` ` ` `// sides of polygons possible ` ` ` `double` `n = ` `360` `/ (` `180` `- a); ` ` ` `if` `(n == (` `int` `)n) ` ` ` `System.out.println(` `"YES"` `); ` ` ` `else` ` ` `System.out.println(` `"NO"` `); ` `} ` ` ` `// Driver code ` `public` `static` `void` `main (String[] args) ` `{` ` ` `double` `a = ` `90` `; ` ` ` ` ` `// function to print` ` ` `// the required answer ` ` ` `makePolygon(a); ` `}` `}` ` ` `// This code is contributed by Bilal` |

## Python3

`# Python 3 implementation ` `# of above approach ` ` ` `# Function to check whether ` `# it is possible to make a` `# regular polygon with a ` `# given angle. ` `def` `makePolygon(a) :` ` ` ` ` `# N denotes the number of sides ` ` ` `# of polygons possible` ` ` `n ` `=` `360` `/` `(` `180` `-` `a)` ` ` ` ` `if` `n ` `=` `=` `int` `(n) :` ` ` `print` `(` `"YES"` `)` ` ` ` ` `else` `:` ` ` `print` `(` `"NO"` `)` ` ` `# Driver Code` `if` `__name__ ` `=` `=` `"__main__"` `:` ` ` `a ` `=` `90` ` ` ` ` `# function calling ` ` ` `makePolygon(a)` ` ` `# This code is contributed ` `# by ANKITRAI1` |

## C#

`// C# implementation of ` `// above approach` `using` `System;` ` ` `class` `GFG ` `{` `// Function to check whether ` `// it is possible to make a` `// regular polygon with a ` `// given angle. ` `static` `void` `makePolygon(` `double` `a) ` `{ ` ` ` `// N denotes the number of ` ` ` `// sides of polygons possible ` ` ` `double` `n = 360 / (180 - a); ` ` ` `if` `(n == (` `int` `)n) ` ` ` `Console.WriteLine(` `"YES"` `); ` ` ` `else` ` ` `Console.WriteLine(` `"NO"` `); ` `} ` ` ` `// Driver code ` `static` `void` `Main() ` `{` ` ` `double` `a = 90; ` ` ` ` ` `// function to print` ` ` `// the required answer ` ` ` `makePolygon(a); ` `}` `}` ` ` `// This code is contributed by mits` |

## PHP

`<?php ` `// PHP implementation of above approach` ` ` `// Function to check whether it ` `// is possible to make a regular` `// polygon with a given angle.` `function` `makePolygon(` `$a` `)` `{` ` ` `// N denotes the number of ` ` ` `// sides of polygons possible` ` ` `$n` `= 360 / (180 - ` `$a` `);` ` ` `if` `(` `$n` `== (int)` `$n` `)` ` ` `echo` `"YES"` `;` ` ` `else` ` ` `echo` `"NO"` `;` `}` ` ` `// Driver code` `$a` `= 90;` ` ` `// function to print the` `// required answer` `makePolygon(` `$a` `);` ` ` `// This code is contributed ` `// by ChitraNayal` `?>` |

**Output:**

YES

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