Check if given number is perfect square
Given a number, check if it is perfect square or not.
Examples :
Input : 2500 Output : Yes 2500 is a perfect square. 50 * 50 = 2500 Input : 2555 Output : No
- Take the square root of the number.
- Take floor/ceil/round of the square root which we got in step 1.
- Subtract value we got in step 2 from the square root.
- If the output of step 3 is 0 then the number is perfect square else not.
C++
// CPP program to find if x is a // perfect square. #include <bits/stdc++.h> using namespace std; bool isPerfectSquare(long double x) { // Find floating point value of // square root of x. long double sr = sqrt(x); // If square root is an integer return ((sr - floor(sr)) == 0); } int main() { long double x = 2500; if (isPerfectSquare(x)) cout << "Yes"; else cout << "No"; return 0; } |
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Java
// Java program to find if x is a // perfect square. class GFG { static boolean isPerfectSquare(double x) { // Find floating point value of // square root of x. double sr = Math.sqrt(x); // If square root is an integer return ((sr - Math.floor(sr)) == 0); } // Driver code public static void main(String[] args) { double x = 2500; if (isPerfectSquare(x)) System.out.print("Yes"); else System.out.print("No"); } } // This code is contributed by Anant Agarwal. |
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Python3
# Python program to find if x is a # perfect square. import math def isPerfectSquare(x): # Find floating point value of # square root of x. sr = math.sqrt(x) # If square root is an integer return ((sr - math.floor(sr)) == 0) # Driver code x = 2500if (isPerfectSquare(x)): print("Yes") else: print("No") # This code is contributed # by Anant Agarwal. |
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C#
// C# program to find if x is a // perfect square. using System; class GFG { static bool isPerfectSquare(double x) { // Find floating point value of // square root of x. double sr = Math.Sqrt(x); // If square root is an integer return ((sr - Math.Floor(sr)) == 0); } // Driver code public static void Main() { double x = 2500; if (isPerfectSquare(x)) Console.WriteLine("Yes"); else Console.WriteLine("No"); } } // This code is contributed by vt_m. |
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PHP
<?php // PHP program to find if x is // a perfect square. function isPerfectSquare($x) { // Find floating point value // of square root of x. $sr = sqrt($x); // If square root is an integer return (($sr - floor($sr)) == 0); } // Driver code $x = 2500; if (isPerfectSquare($x)) echo("Yes"); else echo("No"); // This code is contributed by Ajit. ?> |
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Output:
Yes
To know more about inbuilt sqrt function, refer this Stackoverflow and this StackExchange threads.
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