Check if given number is perfect square

Given a number, check if it is perfect square or not.

Examples :

Input : 2500
Output : Yes
2500 is a perfect square.
50 * 50 = 2500

Input  : 2555
Output : No

  1. Take the square root of the number.
  2. Take floor/ceil/round of the square root which we got in step 1.
  3. Subtract value we got in step 2 from the square root.
  4. If the output of step 3 is 0 then the number is perfect square else not.

C++

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// CPP program to find if x is a 
// perfect square.
#include <bits/stdc++.h>
using namespace std;
  
bool isPerfectSquare(long double x)
{  
  // Find floating point value of 
  // square root of x.
  long double sr = sqrt(x);
  
  // If square root is an integer
  return ((sr - floor(sr)) == 0);
}
  
int main() {
  long double x = 2500;
  if (isPerfectSquare(x))
    cout << "Yes";
  else
    cout << "No";
  return 0;
}

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Java














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// Java program to find if x is a 


// perfect square. 


class GFG { 


      


    static boolean isPerfectSquare(double x)  


    { 


          


        // Find floating point value of 


        // square root of x. 


        double sr = Math.sqrt(x); 


      


        // If square root is an integer 


        return ((sr - Math.floor(sr)) == 0); 


    } 


      


    // Driver code 


    public static void main(String[] args)  


    { 


        double x = 2500; 


          


        if (isPerfectSquare(x)) 


            System.out.print("Yes"); 


        else


            System.out.print("No"); 


    } 


} 


  


// This code is contributed by Anant Agarwal. 



















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Python3














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# Python program to find if x is a  


# perfect square. 


  


import math 


  


def isPerfectSquare(x): 


  


    # Find floating point value of  


    # square root of x. 


    sr = math.sqrt(x) 


   


    # If square root is an integer 


    return ((sr - math.floor(sr)) == 0) 


  


# Driver code 


  


x = 2500


if (isPerfectSquare(x)): 


    print("Yes") 


else: 


    print("No") 


  


# This code is contributed 


# by Anant Agarwal. 



















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C#














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// C# program to find if x is a 


// perfect square. 


using System; 


class GFG { 


      


    static bool isPerfectSquare(double x)  


    { 


          


        // Find floating point value of 


        // square root of x. 


        double sr = Math.Sqrt(x); 


      


        // If square root is an integer 


        return ((sr - Math.Floor(sr)) == 0); 


    } 


      


    // Driver code 


    public static void Main()  


    { 


        double x = 2500; 


          


        if (isPerfectSquare(x)) 


            Console.WriteLine("Yes"); 


        else


            Console.WriteLine("No"); 


    } 


} 


  


// This code is contributed by vt_m. 



















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PHP














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<?php 


// PHP program to find if x is 


// a perfect square. 


  


function isPerfectSquare($x) 


{  


    // Find floating point value  


    // of square root of x. 


    $sr = sqrt($x); 


      


    // If square root is an integer 


    return (($sr - floor($sr)) == 0); 


} 


  


// Driver code 


$x = 2500; 


if (isPerfectSquare($x)) 


    echo("Yes"); 


else


    echo("No"); 


  


// This code is contributed by Ajit. 


?> 



















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Output:


Yes





To know more about inbuilt sqrt function, refer this Stackoverflow and this StackExchange threads.




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