# Check if given number is perfect square

Given a number, check if it is perfect square or not.

Examples :

```Input : 2500
Output : Yes
2500 is a perfect square.
50 * 50 = 2500

Input  : 2555
Output : No
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

1. Take the square root of the number.
2. Take floor/ceil/round of the square root which we got in step 1.
3. Subtract value we got in step 2 from the square root.
4. If the output of step 3 is 0 then the number is perfect square else not.

## C++

 `// CPP program to find if x is a  ` `// perfect square. ` `#include ` `using` `namespace` `std; ` ` `  `bool` `isPerfectSquare(``long` `double` `x) ` `{   ` `  ``// Find floating point value of  ` `  ``// square root of x. ` `  ``long` `double` `sr = ``sqrt``(x); ` ` `  `  ``// If square root is an integer ` `  ``return` `((sr - ``floor``(sr)) == 0); ` `} ` ` `  `int` `main() { ` `  ``long` `double` `x = 2500; ` `  ``if` `(isPerfectSquare(x)) ` `    ``cout << ``"Yes"``; ` `  ``else` `    ``cout << ``"No"``; ` `  ``return` `0; ` `} `

## Java

 `// Java program to find if x is a ` `// perfect square. ` `class` `GFG { ` `     `  `    ``static` `boolean` `isPerfectSquare(``double` `x)  ` `    ``{ ` `         `  `        ``// Find floating point value of ` `        ``// square root of x. ` `        ``double` `sr = Math.sqrt(x); ` `     `  `        ``// If square root is an integer ` `        ``return` `((sr - Math.floor(sr)) == ``0``); ` `    ``} ` `     `  `    ``// Driver code ` `    ``public` `static` `void` `main(String[] args)  ` `    ``{ ` `        ``double` `x = ``2500``; ` `         `  `        ``if` `(isPerfectSquare(x)) ` `            ``System.out.print(``"Yes"``); ` `        ``else` `            ``System.out.print(``"No"``); ` `    ``} ` `} ` ` `  `// This code is contributed by Anant Agarwal. `

## Python3

 `# Python program to find if x is a  ` `# perfect square. ` ` `  `import` `math ` ` `  `def` `isPerfectSquare(x): ` ` `  `    ``# Find floating point value of  ` `    ``# square root of x. ` `    ``sr ``=` `math.sqrt(x) ` `  `  `    ``# If square root is an integer ` `    ``return` `((sr ``-` `math.floor(sr)) ``=``=` `0``) ` ` `  `# Driver code ` ` `  `x ``=` `2500` `if` `(isPerfectSquare(x)): ` `    ``print``(``"Yes"``) ` `else``: ` `    ``print``(``"No"``) ` ` `  `# This code is contributed ` `# by Anant Agarwal. `

## C#

 `// C# program to find if x is a ` `// perfect square. ` `using` `System; ` `class` `GFG { ` `     `  `    ``static` `bool` `isPerfectSquare(``double` `x)  ` `    ``{ ` `         `  `        ``// Find floating point value of ` `        ``// square root of x. ` `        ``double` `sr = Math.Sqrt(x); ` `     `  `        ``// If square root is an integer ` `        ``return` `((sr - Math.Floor(sr)) == 0); ` `    ``} ` `     `  `    ``// Driver code ` `    ``public` `static` `void` `Main()  ` `    ``{ ` `        ``double` `x = 2500; ` `         `  `        ``if` `(isPerfectSquare(x)) ` `            ``Console.WriteLine(``"Yes"``); ` `        ``else` `            ``Console.WriteLine(``"No"``); ` `    ``} ` `} ` ` `  `// This code is contributed by vt_m. `

## PHP

 ` `

Output:

```Yes
```

To know more about inbuilt sqrt function, refer this Stackoverflow and this StackExchange threads.

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