Check if given number is perfect square

Given a number, check if it is perfect square or not.

Examples :

Input : 2500
Output : Yes
2500 is a perfect square.
50 * 50 = 2500

Input  : 2555
Output : No

  1. Take the square root of the number.
  2. Take floor/ceil/round of the square root which we got in step 1.
  3. Subtract value we got in step 2 from the square root.
  4. If the output of step 3 is 0 then the number is perfect square else not.

C++

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// CPP program to find if x is a 
// perfect square.
#include <bits/stdc++.h>
using namespace std;
  
bool isPerfectSquare(long double x)
{  
  // Find floating point value of 
  // square root of x.
  long double sr = sqrt(x);
  
  // If square root is an integer
  return ((sr - floor(sr)) == 0);
}
  
int main() {
  long double x = 2500;
  if (isPerfectSquare(x))
    cout << "Yes";
  else
    cout << "No";
  return 0;
}

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Java

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// Java program to find if x is a
// perfect square.
class GFG {
      
    static boolean isPerfectSquare(double x) 
    {
          
        // Find floating point value of
        // square root of x.
        double sr = Math.sqrt(x);
      
        // If square root is an integer
        return ((sr - Math.floor(sr)) == 0);
    }
      
    // Driver code
    public static void main(String[] args) 
    {
        double x = 2500;
          
        if (isPerfectSquare(x))
            System.out.print("Yes");
        else
            System.out.print("No");
    }
}
  
// This code is contributed by Anant Agarwal.

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Python3

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# Python program to find if x is a 
# perfect square.
  
import math
  
def isPerfectSquare(x):
  
    # Find floating point value of 
    # square root of x.
    sr = math.sqrt(x)
   
    # If square root is an integer
    return ((sr - math.floor(sr)) == 0)
  
# Driver code
  
x = 2500
if (isPerfectSquare(x)):
    print("Yes")
else:
    print("No")
  
# This code is contributed
# by Anant Agarwal.

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C#

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// C# program to find if x is a
// perfect square.
using System;
class GFG {
      
    static bool isPerfectSquare(double x) 
    {
          
        // Find floating point value of
        // square root of x.
        double sr = Math.Sqrt(x);
      
        // If square root is an integer
        return ((sr - Math.Floor(sr)) == 0);
    }
      
    // Driver code
    public static void Main() 
    {
        double x = 2500;
          
        if (isPerfectSquare(x))
            Console.WriteLine("Yes");
        else
            Console.WriteLine("No");
    }
}
  
// This code is contributed by vt_m.

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PHP

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<?php
// PHP program to find if x is
// a perfect square.
  
function isPerfectSquare($x)
    // Find floating point value 
    // of square root of x.
    $sr = sqrt($x);
      
    // If square root is an integer
    return (($sr - floor($sr)) == 0);
}
  
// Driver code
$x = 2500;
if (isPerfectSquare($x))
    echo("Yes");
else
    echo("No");
  
// This code is contributed by Ajit.
?>

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Output:

Yes

To know more about inbuilt sqrt function, refer this Stackoverflow and this StackExchange threads.



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