# Check if both halves of a string are Palindrome or not

• Last Updated : 02 Feb, 2022

Given a string str, the task is to check whether the given string can be split into two halves, each of which is palindromic. If it is possible, print Yes. Otherwise, print No.
Examples:

Input: str = “naan”
Output: No
Explanation:
Since both halves “na” and “an” are not palindrome.
Output: Yes
Explanation:
Since both half “mom” and “dad” are palindromes.

Approach:
Follow the steps below to solve the problem:

• Iterate over the first ((N / 2) / 2 – 1) indices of the string.
• Simultaneously check if both the halves are palindrome or not by the following two conditions:
• If S[i] is not equal to S[N/2 – 1 – i], then first half is not palindromic.
• If S[N/2 + i] is not equal to S[N – 1 – i], then second half is not palindromic.
• If none of the above condition is satisfied even once during the iteration, then both halves are palindromic. Print Yes.
• Otherwise, print No.

Below is the implementation of the above approach:

## C++

 `// C++ Program to check whether``// both halves of a string is``// Palindrome or not``#include ``using` `namespace` `std;` `// Function to check if both halves``// of a string are palindrome or not``void` `checkPalindrome(string S)``{``    ``// Length of string``    ``int` `N = S.size();` `    ``// Initialize both part as true``    ``bool` `first_half = ``true``;``    ``bool` `second_half = ``true``;` `    ``int` `cnt = (N / 2) - 1;` `    ``for` `(``int` `i = 0; i < ((N / 2) / 2); i++) {` `        ``// If first half is not palindrome``        ``if` `(S[i] != S[cnt]) {``            ``first_half = ``false``;``            ``break``;``        ``}` `        ``// If second half is not palindrome``        ``if` `(S[N / 2 + i] != S[N / 2 + cnt]) {``            ``second_half - ``false``;``            ``break``;``        ``}` `        ``cnt--;``    ``}` `    ``// If both halves are Palindrome``    ``if` `(first_half && second_half) {``        ``cout << ``"Yes"` `<< endl;``    ``}``    ``else` `{``        ``cout << ``"No"` `<< endl;``    ``}``}` `int` `main()``{``    ``string S = ``"momdad"``;` `    ``checkPalindrome(S);` `    ``return` `0;``}`

## Java

 `// Java Program to check whether``// both halves of a string is``// Palindrome or not``public` `class` `Main {` `    ``// Function to check and return if``    ``// both halves of a string are``    ``// palindromic or not``    ``public` `static` `void` `checkPalindrome(``        ``String S)``    ``{``        ``// Length of string``        ``int` `N = S.length();` `        ``// Initialize both part as true``        ``boolean` `first_half = ``true``;``        ``boolean` `second_half = ``true``;` `        ``int` `cnt = (N / ``2``) - ``1``;` `        ``for` `(``int` `i = ``0``; i < (N / ``2``); i++) {` `            ``// If first half is not palindrome``            ``if` `(S.charAt(i) != S.charAt(cnt)) {``                ``first_half = ``false``;``                ``break``;``            ``}` `            ``// If second half is not palindrome``            ``if` `(S.charAt(N / ``2` `+ i)``                ``!= S.charAt(N / ``2` `+ cnt)) {``                ``second_half = ``false``;``                ``break``;``            ``}` `            ``cnt--;``        ``}` `        ``// If both halves are Palindrome``        ``if` `(first_half && second_half) {``            ``System.out.println(``"Yes"``);``        ``}``        ``else` `{``            ``System.out.println(``"No"``);``        ``}``    ``}` `    ``// Driver Code``    ``public` `static` `void` `main(String[] args)``    ``{` `        ``String S = ``"momdad"``;` `        ``checkPalindrome(S);``    ``}``}`

## Python3

 `# Python3 program to check whether``# both halves of a string is``# palindrome or not` `# Function to check if both halves``# of a string are palindrome or not``def` `checkPalindrome(S):``    ` `    ``# Length of string``    ``n ``=` `len``(S)``    ` `    ``# Initialize both part as true``    ``first_half ``=` `True``    ``second_half ``=` `True``    ` `    ``cnt ``=` `(n ``/``/` `2``) ``-` `1``    ` `    ``for` `i ``in` `range``(``0``, ``int``((n ``/` `2``) ``/` `2``)):``        ` `        ``# If first half is not palindrome``        ``if` `(S[i] !``=` `S[cnt]):``            ``first_half ``=` `False``            ``break``            ` `        ``# If second half is not palindrome``        ``if` `(S[n ``/``/` `2` `+` `i] !``=` `S[n ``/``/` `2` `+` `cnt]):``            ``second_half ``=` `False``            ``break``            ` `        ``cnt ``-``=` `1``        ` `    ``# If both halves are palindrome``    ``if` `(first_half ``and` `second_half):``        ``print``(``'Yes'``, end ``=` `'')``    ``else``:``        ``print``(``'No'``, end ``=` `'')` `# Driver code``if` `__name__``=``=``'__main__'``:``    ` `    ``S ``=` `'momdad'``    ` `    ``checkPalindrome(S)``                ` `# This code is contributed by virusbuddah_`

## C#

 `// C# program to check whether``// both halves of a string is``// Palindrome or not``using` `System;` `class` `GFG{` `// Function to check and return if``// both halves of a string are``// palindromic or not``public` `static` `void` `checkPalindrome(String S)``{``    ` `    ``// Length of string``    ``int` `N = S.Length;` `    ``// Initialize both part as true``    ``bool` `first_half = ``true``;``    ``bool` `second_half = ``true``;` `    ``int` `cnt = (N / 2) - 1;` `    ``for``(``int` `i = 0; i < (N / 2); i++)``    ``{``        ` `        ``// If first half is not palindrome``        ``if` `(S[i] != S[cnt])``        ``{``            ``first_half = ``false``;``            ``break``;``        ``}` `        ``// If second half is not palindrome``        ``if` `(S[N / 2 + i] != S[N / 2 + cnt])``        ``{``            ``second_half = ``false``;``            ``break``;``        ``}``        ``cnt--;``    ``}` `    ``// If both halves are Palindrome``    ``if` `(first_half && second_half)``    ``{``        ``Console.Write(``"Yes"``);``    ``}``    ``else``    ``{``        ``Console.Write(``"No"``);``    ``}``}` `// Driver code``public` `static` `void` `Main()``{``    ``String S = ``"momdad"``;` `    ``checkPalindrome(S);``}``}` `// This code is contributed by grand_master`

## Javascript

 ``

Output:

`Yes`

Time Complexity: O(N)
Auxiliary Space: O(1)

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