# Check if all the set bits of the binary representation of N are at least K places away

Given numbers N and K, The task to check if all the set bits of the binary representation of N are at least K places away.

Examples:

```Input: N = 5, K = 1
Output: YES
Explanation:
Binary of 5 is 101.
The 1's are 1 place far from each other.

Input: N = 10, K = 2
Output: NO
Explanation:
Binary of 10 is 1010.
The 1's are not at least 2 places far from each other.
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach:

1. Iterate Over all the bits in the binary representation of N and maintain a variable ‘count’ initialize to 0.
2. Whenever you find a set bit(1), check if count <= K. If not return false.
3. If you find a unset bit(0), increases the value of count by 1.

Below is the implementation of the above approach.

 `// C++ program to check if all the set ` `// bits of the binary representation ` `// of N are at least K places away. ` `#include ` `using` `namespace` `std; ` ` `  `bool` `CheckBits(``int` `N, ``int` `K) ` `{ ` `    ``// Initialize check and count ` `    ``// with 0 ` `    ``int` `check = 0; ` `    ``int` `count = 0; ` ` `  `    ``for` `(``int` `i = 31; i >= 0; i--) ` `    ``{ ` ` `  `        ``// The i-th bit is a set bit ` `        ``if` `((1 << i) & N) ` `        ``{ ` ` `  `            ``// This is the first set bit so, ` `            ``// start calculating all the ` `            ``// distances between consecutive ` `            ``// bits from here ` `            ``if` `(check == 0) ` `            ``{ ` `                ``check = 1; ` `            ``} ` `            ``else` `            ``{ ` `                ``// If count is less than K  ` `                ``// return false ` `                ``if` `(count < K) ` `                ``{ ` `                    ``return` `false``; ` `                ``} ` `            ``} ` `            ``count = 0; ` `        ``} ` `        ``else` `        ``{ ` `            ``// Adding the count as the ` `            ``// number of zeroes increase ` `            ``// between set bits ` `            ``count++; ` `        ``} ` `    ``} ` ` `  `    ``return` `true``; ` `} ` `// Driver code ` `int` `main() ` `{ ` ` `  `    ``int` `N = 5; ` `    ``int` `K = 1; ` ` `  `    ``if``(CheckBits(N, K)) ` `    ``{ ` `        ``cout << ``"YES"``; ` `    ``} ` `    ``else` `    ``{ ` `        ``cout << ``"NO"``; ` `    ``} ` ` `  ` `  ` `  `    ``return` `0; ` `} `

Output:

```YES
```

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