Given a binary string str, the task is to check if all the 1’s in the string are equidistant or not. The term equidistant means that the distance between every two adjacent 1’s is same. Note that the string contains at least two 1’s.
Input: str = “00111000”
The distance between all the 1’s is same and is equal to 1.
Input: str = “0101001”
The distance between the 1st and the 2nd 1’s is 2
and the distance between the 2nd and the 3rd 1’s is 3.
Approach: Store the position of all the 1’s in the string in a vector and then check if the difference between each two consecutive positions is same or not.
Below is the implementation of the above approach:
Time Complexity: O(N) where N is the length of the string.
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