Check if a string is suffix of another

Difficulty Level : Easy
Last Updated : 09 Nov, 2020

Given two strings s1 and s2, check if s1 is a suffix of s2. Or in simple words we need to find whether string s2 ends with string s1.
Examples :

Input : s1 = "geeks" and s2 = "geeksforgeeks"
Output : Yes

Input : s1 = "world", s2 = "my first code is hello world"
Output : Yes

Input : s1 = "geeks" and s2 = "geeksforGeek"
Output : No

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Method 1 (Writing our own code)

C++

// CPP program to find if a string is  
// suffix of another 
#include <iostream> 
#include <string> 
using namespace std; 
  
bool isSuffix(string s1, string s2) 
{ 
    int n1 = s1.length(), n2 = s2.length(); 
    if (n1 > n2) 
      return false; 
    for (int i=0; i<n1; i++) 
       if (s1[n1 - i - 1] != s2[n2 - i - 1]) 
           return false; 
    return true; 
} 
  
int main() 
{ 
    string s1 = "geeks", s2 = "geeksforgeeks"; 
  
    // Test case-sensitive implementation  
    // of endsWith function 
    bool result = isSuffix(s1, s2); 
  
    if (result)  
        cout << "Yes"; 
    else
        cout << "No"; 
  
    return 0; 
} 

Java

// Java program to find if a string is  
// suffix of another 
  
class GFG 
{ 
    static boolean isSuffix(String s1, String s2) 
    { 
        int n1 = s1.length(), n2 = s2.length(); 
        if (n1 > n2) 
        return false; 
        for (int i=0; i<n1; i++) 
        if (s1.charAt(n1 - i - 1) != s2.charAt(n2 - i - 1)) 
            return false; 
        return true; 
    } 
      
    public static void main(String []args) 
    { 
        String s1 = "geeks", s2 = "geeksforgeeks"; 
      
        // Test case-sensitive implementation  
        // of endsWith function 
        boolean result = isSuffix(s1, s2); 
      
        if (result)  
            System.out.println( "Yes"); 
        else
            System.out.println("No"); 
      
          
    } 
  
} 
  
// This code is contributed by iAyushRaj 

Python 3

# Python 3 program to find if a  
# string is suffix of another 
def isSuffix(s1, s2): 
      
    n1 = len(s1) 
    n2 = len(s2) 
    if (n1 > n2): 
        return False
    for i in range(n1): 
        if(s1[n1 - i - 1] != s2[n2 - i - 1]): 
            return False
    return True
  
# Driver Code 
if __name__ == "__main__": 
      
    s1 = "geeks"
    s2 = "geeksforgeeks"
  
    # Test case-sensitive implementation  
    # of endsWith function 
    result = isSuffix(s1, s2) 
  
    if (result):  
        print("Yes") 
    else: 
        print( "No") 
  
# This code is contributed 
# by ChitraNayal 

C#

// C# program to find if a string is  
// suffix of another 
  
using System; 
class GFG 
{ 
    static bool isSuffix(string s1, string s2) 
    { 
        int n1 = s1.Length, n2 = s2.Length; 
        if (n1 > n2) 
        return false; 
        for (int i=0; i<n1; i++) 
        if (s1[n1 - i - 1] != s2[n2 - i - 1]) 
            return false; 
        return true; 
    } 
      
    public static void Main() 
    { 
        string s1 = "geeks", s2 = "geeksforgeeks"; 
      
        // Test case-sensitive implementation  
        // of endsWith function 
        bool result = isSuffix(s1, s2); 
      
        if (result)  
            Console.WriteLine( "Yes"); 
        else
            Console.WriteLine("No"); 
      
          
    } 
  
} 
  
// This code is contributed by iAyushRaj 

PHP

<?php 
// PHP program to find if a  
// string is suffix of another 
function isSuffix($s1, $s2) 
{ 
    $n1 = ($s1);  
    $n2 = strlen($s2); 
    if ($n1 > $n2) 
    return false; 
    for ($i = 0; $i < $n1; $i++) 
    if ($s1[$n1 - $i - 1] != $s2[$n2 - $i - 1]) 
        return false; 
    return true; 
} 
// Driver Code 
$s1 = "geeks"; 
$s2 = "geeksforgeeks"; 
  
// Test case-sensitive implementation  
// of endsWith function 
$result = isSuffix($s1, $s2); 
  
if ($result)  
    echo "Yes"; 
else
    echo "No"; 
  
// This code is contributed by m_kit 
?> 

Output:

Yes

Method 2 (Using boost library in C++)
Since std::string class does not provide any endWith() function which a string ends with another string so we will be using Boost Library. Make sure to include #include boost/algorithm/string.hpp and #include string to run the code fine.

C++

// CPP program to find if a string is  
// suffix of another 
#include <boost/algorithm/string.hpp> 
#include <iostream> 
#include <string> 
using namespace std; 
  
int main() 
{ 
    string s1 = "geeks", s2 = "geeksforgeeks"; 
  
    // Test case-sensitive implementation  
    // of endsWith function 
    bool result = boost::algorithm::ends_with(s2, s1); 
  
    if (result)  
        cout << "Yes"; 
    else
        cout << "No"; 
  
    return 0; 
} 

Java

// Java program to find if a string is  
// suffix of another 
class GFG 
{ 
  
    public static void main(String[] args)  
    { 
        String s1 = "geeks", s2 = "geeksforgeeks"; 
  
        // Test case-sensitive implementation  
        // of endsWith function 
        boolean result = s2.endsWith(s1); 
  
        if (result)  
                System.out.println("Yes"); 
        else
            System.out.println("No"); 
    } 
}  
  
// This code is contributed by 29AjayKumar 

Python3

# Python3 program to find if a string is  
# suffix of another 
  
if __name__ == '__main__': 
    s1 = "geeks"; 
    s2 = "geeksforgeeks"; 
      
    # Test case-sensitive implementation 
    # of endsWith function 
    result = s2.endswith(s1); 
      
    if (result): 
        print("Yes"); 
    else: 
        print("No"); 
      
# This code is contributed by Rajput-Ji 

C#

// C# program to find if a string is  
// suffix of another  
using System; 
  
class GFG  
{  
    // Driver code 
    public static void Main(String[] args)  
    {  
        String s1 = "geeks", s2 = "geeksforgeeks";  
  
        // Test case-sensitive implementation  
        // of endsWith function  
        bool result = s2.EndsWith(s1);  
  
        if (result)  
                Console.WriteLine("Yes");  
        else
            Console.WriteLine("No");  
    }  
}  
  
// This code contributed by Rajput-Ji 

Output :

Yes

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Recommended: Please try your approach on {IDE} first, before moving on to the solution.

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