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Check if a string contains a palindromic sub-string of even length
• Difficulty Level : Easy
• Last Updated : 07 Jan, 2019

S is string containing only lowercase English alphabets. We need to find if there exists at least one palindromic sub-string whose length is even.

Examples:

```Input  : aassss
Output : YES

Input  : gfg
Output : NO
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Notice that a palindrome of even length must contain two same alphabets in the middle. So we just need to check for this condition. If we find two consecutive same alphabets in the string then we output “YES” otherwise “NO”.

Below is the implementation:

## C++

 `// CPP program to check if there is a substring``// palindrome of even length.``#include ``using` `namespace` `std;`` ` `// function to check if two consecutive same ``// characters are present``bool` `check(string s)``{``    ``for` `(``int` `i = 0; i < s.length() - 1; i++)``        ``if` `(s[i] == s[i + 1])``            ``return` `true``;``    ``return` `false``;``}`` ` `int` `main()``{``    ``string s = ``"xzyyz"``;``    ``if` `(check(s))``        ``cout << ``"YES"` `<< endl;``    ``else``        ``cout << ``"NO"` `<< endl;``    ``return` `0;``}`

## Java

 `// Java program to check if there is a substring ``// palindrome of even length. `` ` `class` `GFG {`` ` ` ` `// function to check if two consecutive same ``// characters are present ``static` `boolean` `check(String s) ``{ ``    ``for` `(``int` `i = ``0``; i < s.length() - ``1``; i++) ``        ``if` `(s.charAt(i) == s.charAt(i+``1``)) ``            ``return` `true``; ``    ``return` `false``; ``} `` ` `// Driver Code ``    ``public` `static` `void` `main(String[] args) {`` ` `        ``String s = ``"xzyyz"``; ``    ``if` `(check(s)) ``              ``System.out.println(``"YES"``);``    ``else``        ``System.out.println(``"NO"``);``    ``}``}`

## Python3

 `# Python 3 program to check if there is ``# a substring palindrome of even length.`` ` `# function to check if two consecutive``# same characters are present``def` `check(s):`` ` `    ``for` `i ``in` `range` `(``0``, ``len``(s)):``        ``if` `(s[i] ``=``=` `s[i ``+` `1``]):``            ``return` `True``             ` `    ``return` `False`` ` `# Driver Code``s ``=` `"xzyyz"``if``(check(s)):``    ``print``(``"YES"``)``else``:``    ``print``(``"NO"``)``     ` `# This code is contributed``# by iAyushRAJ`

## C#

 `// C# program to check if there is a substring ``// palindrome of even length. ``using` `System; ``public` `class` `GFG {`` ` ` ` `// function to check if two consecutive same ``// characters are present ``static` `bool` `check(String s) ``{ ``    ``for` `(``int` `i = 0; i < s.Length - 1; i++) ``        ``if` `(s[i] == s[i+1]) ``            ``return` `true``; ``    ``return` `false``; ``} `` ` `// Driver Code ``    ``public` `static` `void` `Main() {`` ` `        ``String s = ``"xzyyz"``; ``    ``if` `(check(s)) ``              ``Console.WriteLine(``"YES"``);``    ``else``        ``Console.WriteLine(``"NO"``);``    ``}``}`

## PHP

 ``
Output:
```YES
```

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