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Check if a point lies inside a rectangle | Set-2

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  • Last Updated : 18 Aug, 2022
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Given coordinates of bottom-left and top-right corners of a rectangle. Check if a point (x, y) lies inside this rectangle or not.

Examples: 

Input: bottom-left: (0, 0), top-right: (10, 8), point: (1, 5) 
Output: Yes

Input: bottom-left: (-1, 4), top-right:(2, 3), point:(0, 4) 
Output: No

This problem is already discussed in a previous post. In this post, we have discussed a new approach.

Approach: If we observe carefully, It will be clear that for a point to be lie inside the rectangle, it should be lie inside the x-coordinate (x1, x2) of the rectangle as well as it should also lie inside the y-coordinate (y1, y2) of the rectangle.

Algorithm:

  • Check if the x-coordinate of the given point (x, y) is lie inside the x-coordinate (x1, x2) of the rectangle, i.e, x > x1 and x < x2
  • Check if the y-coordinate of the given point (x, y) is lie inside the y-coordinate (y1, y2) of the rectangle, i.e, y > y1 and y < y2
  • If both the above condition satisfy then, 
    • The given point completely lie inside the rectangle.
  • Otherwise, not.

Below is the implementation of the above approach:  

C++




// CPP program to Check if a
// point lies on or inside a rectangle | Set-2
#include <bits/stdc++.h>
using namespace std;
 
// function to find if given point
// lies inside a given rectangle or not.
bool FindPoint(int x1, int y1, int x2,
               int y2, int x, int y)
{
    if (x > x1 and x < x2 and y > y1 and y < y2)
        return true;
 
    return false;
}
 
// Driver code
int main()
{
    // bottom-left and top-right
    // corners of rectangle
    int x1 = 0, y1 = 0, x2 = 10, y2 = 8;
 
    // given point
    int x = 1, y = 5;
 
    // function call
    if (FindPoint(x1, y1, x2, y2, x, y))
        cout << "Yes";
    else
        cout << "No";
 
    return 0;
}

C




// C program to Check if a
// point lies on or inside a rectangle | Set-2
#include <stdio.h>
#include <stdbool.h>
 
// function to find if given point
// lies inside a given rectangle or not.
bool FindPoint(int x1, int y1, int x2, int y2, int x, int y)
{
    if (x > x1 && x < x2 && y > y1 && y < y2)
        return true;
 
    return false;
}
 
// Driver code
int main()
{
    // bottom-left and top-right
    // corners of rectangle
    int x1 = 0, y1 = 0, x2 = 10, y2 = 8;
 
    // given point
    int x = 1, y = 5;
 
    // function call
    if (FindPoint(x1, y1, x2, y2, x, y))
        printf("Yes");
    else
        printf("No");
 
    return 0;
}
 
// This code is contributed by kothavvsaakash.

Java




// Java program to Check if
// a point lies on or inside
// a rectangle | Set-2
class GFG
{
 
// function to find if given point
// lies inside a given rectangle or not.
static boolean FindPoint(int x1, int y1, int x2,
                         int y2, int x, int y)
{
if (x > x1 && x < x2 &&
    y > y1 && y < y2)
    return true;
 
return false;
}
 
// Driver code
public static void main(String[] args)
{
     
    // bottom-left and top-right
    // corners of rectangle
    int x1 = 0, y1 = 0,
        x2 = 10, y2 = 8;
 
    // given point
    int x = 1, y = 5;
 
    // function call
    if (FindPoint(x1, y1, x2, y2, x, y))
        System.out.println("Yes");
    else
        System.out.println("No");
}
}
 
// This code is contributed
// by ChitraNayal

Python3




# Python3 program to Check
# if a point lies on or
# inside a rectangle | Set-2
 
# function to find if
# given point lies inside
# a given rectangle or not.
def FindPoint(x1, y1, x2,
              y2, x, y) :
    if (x > x1 and x < x2 and
        y > y1 and y < y2) :
        return True
    else :
        return False
 
# Driver code
if __name__ == "__main__" :
 
    # bottom-left and top-right
    # corners of rectangle.
    # use multiple assignment
    x1 , y1 , x2 , y2 = 0, 0, 10, 8
 
    # given point
    x, y = 1, 5
 
    # function call
    if FindPoint(x1, y1, x2,
                 y2, x, y) :
        print("Yes")
    else :
        print("No")
 
# This code is contributed
# by Ankit Rai

C#




// C# program to Check if a
// point lies on or inside
// a rectangle | Set-2
using System;
 
class GFG
{
 
// function to find if given
// point lies inside a given
// rectangle or not.
static bool FindPoint(int x1, int y1, int x2,
                      int y2, int x, int y)
{
if (x > x1 && x < x2 &&
    y > y1 && y < y2)
    return true;
 
return false;
}
 
// Driver code
public static void Main()
{
     
    // bottom-left and top-right
    // corners of rectangle
    int x1 = 0, y1 = 0,
        x2 = 10, y2 = 8;
 
    // given point
    int x = 1, y = 5;
 
    // function call
    if (FindPoint(x1, y1, x2, y2, x, y))
        Console.Write("Yes");
    else
        Console.Write("No");
}
}
 
// This code is contributed
// by ChitraNayal

PHP




<?php
// PHP program to Check if
// a point lies on or inside
// a rectangle | Set-2
 
// function to find if given
// point lies inside a given
// rectangle or not.
function FindPoint($x1, $y1, $x2,
                   $y2, $x, $y)
{
    if ($x > $x1 and $x < $x2 and
        $y > $y1 and $y < $y2)
        return true;
 
    return false;
}
 
// Driver code
 
// bottom-left and top-right
// corners of rectangle
$x1 = 0; $y1 = 0;
$x2 = 10; $y2 = 8;
 
// given point
$x = 1; $y = 5;
 
// function call
if (FindPoint($x1, $y1, $x2,
              $y2, $x, $y))
    echo "Yes";
else
    echo "No";
 
// This code is contributed
// by Akanksha Rai(Abby_akku)
?>

Javascript




<script>
 
// Javascript program to Check if a
// point lies on or inside a rectangle | Set-2
 
// function to find if given point
// lies inside a given rectangle or not.
function FindPoint(x1, y1, x2,
            y2, x, y)
{
    if (x > x1 && x < x2 && y > y1 && y < y2)
        return true;
 
    return false;
}
 
// Driver code
  
    // bottom-left and top-right
    // corners of rectangle
    let x1 = 0, y1 = 0, x2 = 10, y2 = 8;
 
    // given point
    let x = 1, y = 5;
 
    // function call
    if (FindPoint(x1, y1, x2, y2, x, y))
        document.write("Yes");
    else
        document.write("No");
 
// This code is contributed by Mayank Tyagi
 
</script>

Output

Yes

Time Complexity: O(1)
Auxiliary Space: O(1)


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